Equilibrium distance for solar sail

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Homework Help Overview

The discussion revolves around determining the equilibrium distance for a solar sail in relation to a star, where radiation pressure equals gravitational force. The original poster explores the mathematical relationships involved, including the radiation pressure and gravitational equations, while considering the mass per unit area and stellar luminosity.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to derive an equation for equilibrium distance but encounters issues with variable cancellation. Some participants question the assumption of a specific equilibrium distance, while others suggest that equilibrium might be present at all distances due to the nature of the forces involved.

Discussion Status

Participants are actively engaging with the concepts, questioning assumptions about equilibrium and the conditions under which a solar sail would drift or fall towards a star. There is a recognition that the mass to area ratio of the sail plays a critical role in its behavior, though no consensus on a definitive solution has been reached.

Contextual Notes

There is an indication that the discussion is not a formal homework assignment, but rather an exploration of a theoretical problem. The original poster expresses uncertainty about the need for calculus in their approach.

cyberdiver
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This is not actually a homework assignment, but something I decided to try in my own time. I wanted to find the radius from a star at which a solar sail would be held at equilibrium (radiation pressure = gravity), given mass per unit area and stellar luminosity at a reference radius.

So I attempted the following:
Pressure of radiation and pressure of gravity are equal and opposing:
p_{radiation}=-p_{gravity}
Subsititute radiation pressure equation and gravity equation (rho_A is areal density, E_F is energy flux):
2 \cdot \frac{E_F}{c} = -{\rho}_A \cdot g
Substitute inverse square law equation into E_F, areal density equation into rho_A, and the law of universal gravitation equation:
2 \cdot \frac{E_{F0} \cdot (\frac{r_0}{r})^2}{c} = -\frac{m}{A} \cdot \frac{G \cdot M}{r^2}
Attempt to make r^2 the subject:
2 \cdot E_{F0} \cdot \frac{r_0^2}{r^2} \cdot A \cdot r^2 = -m \cdot G \cdot M

The problem here is that r^2 and r^2 will cancel out, making the equation useless. How else could I solve this problem? Does it require calculus?
 
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You are assuming there is a particular distance where a balance is struck. Your equations are telling you something else.
 
Hold on. Is it because radiation pressure and gravity both follow the inverse square law, so the equilibrium is at all distances?
 
cyberdiver said:
Hold on. Is it because radiation pressure and gravity both follow the inverse square law, so the equilibrium is at all distances?
Yes.
 
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But if the solar sail is heavy enough, it would start falling toward the star, wouldn't it?
 
cyberdiver said:
But if the solar sail is heavy enough, it would start falling toward the star, wouldn't it?
whether the sail drifts away from the star or falls towards it will depend on its mass to area ratio and the star's mass to flux ratio. What it won't depend on is the starting position.
 
So the sail can only reach a state of equilibrium if its areal density is just right, otherwise it would drift?
 
cyberdiver said:
So the sail can only reach a state of equilibrium if its areal density is just right, otherwise it would drift?
Yes.
 
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I understand now. Thank you very much!
 

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