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Homework Help: Force Equilibrium of house painter

  1. Nov 14, 2007 #1
    1. The problem statement, all variables and given/known data

    A house painter is standing on a uniform, horizontal platform that is held in equilibrium by two cables attached to supports on the roof. The painter has a mass of 72 kg and the mass of the platform is 19.7 kg. The distance from the left end of the platform to where the painter is standing is d = 2.2 m and the total length of the platform is 5.4 m.

    fig-060.gif

    (a) How large is the force exerted by the left-hand cable on the platform?
    ____ N

    (b) How large is the force exerted by the right-hand cable?
    ____ N


    2. Relevant equations
    ?????????


    3. The attempt at a solution

    How do you do this when there is two different points of rotation??
     
  2. jcsd
  3. Nov 14, 2007 #2
    OK well firstly you need to draw a free body diagram with all the forces you are told and their distances.

    You are aware of the formula;
    [tex]
    \sum {M_{CW} } = \sum {M_{ACW} }
    [/tex]
    ?
     
  4. Nov 14, 2007 #3
    what does this mean? the sum of ..masses?
     
  5. Nov 14, 2007 #4
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