Force exerted by external field

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Homework Help Overview

The discussion revolves around the concept of forces acting on a charged particle in a uniform electric field, specifically focusing on how this field can counteract the force of gravity, rendering the particle effectively weightless. The problem involves calculating the strength of the electric field required for a proton to achieve this state.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between the forces due to gravity and the electric field, questioning the sign convention for these forces. There is an attempt to clarify the conditions under which the forces cancel each other out.

Discussion Status

The discussion is active, with participants providing insights into the relationship between the forces and addressing confusion regarding the directionality of gravity and electric force. Some guidance has been offered on how to set up the equations, but there remains uncertainty about the sign conventions used in the calculations.

Contextual Notes

Participants are navigating the implications of defining forces as positive or negative based on their directions, and there is an emphasis on the need for these forces to be equal and opposite for the proton to be weightless.

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Homework Statement



A uniform electrical field can exert a force on a charged particle that effectively neutralizes the force of gravity on the particle causing it to be weightless. What is the strength of the electrical field for a proton?

q = 2.45x10^-14
mass of proton = 10.21x10^-12 kg

Homework Equations



F=qE


The Attempt at a Solution



My question is what does that statement make the force?

What I think it means is that gravity is 9.8 m/s^2 so to cancel it out gravity is -9.8m/s^2.
So to sovle it you would use F=mg
so, F = (-9.8m/s^2)(10.21x10^-12 kg)
So Force = -1.00058x^-10
Is that right?

thanks
 
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yes what you have there is essentially correct, just have to take it 1 step further

For the proton to be weightless, the force exerted on the proton by the electric field has to be exactly equal to the force of Gravity.

Force due to Electric Field
F(e) = q * E

Force due to Gravity
F(g) = m * g

So for the proton to be weightless, we have:
F(e) = F(g)
Substituting:
qE = mg
Solve for E
E = mg/q

calculate E and you have the strength of the Electric Field required for the proton to be weightless
 
Still counfused whether gravity is negative or positive?

Everything else makes sense thanks.
 
All you want is two forces to cancel.
Force due to gravity is pointing downwards.
So you want Fe to point upwards.
 
It doesn't really matter if gravity is +ve or -ve
The important thing to realize, as graphene said, is that the two forces are working in opposite directions. Gravity is pulling down, the Electric Field is pushing up.
So for something to be weightless, the force pushing up has to be exactly the same as the force pulling down.

The positive and negative is totally up to you. If you want to call the up direction positive then gravity is negative and the electric force is positive. If you want to call the down direction positive, then gravity is positive and the electric force is negative.

As long as they are opposite and equal the sign doesn't matter because when you add them up, you will get a Net force of Zero and that's what makes the proton weightless.
 

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