Force exerted by M1 on M2 problem

  • Thread starter Thread starter JSmithDawg
  • Start date Start date
  • Tags Tags
    Force
Click For Summary
In the discussion about the force exerted by M1 on M2, participants analyze a scenario where M2 (4 kg) is subjected to a 36N force on a frictionless surface, while M1 (20 kg) is connected. Newton's third law is emphasized, noting that forces act in pairs, but the initial assumption that M1 exerts 36N on M2 is corrected. The correct approach involves calculating the system's acceleration using F=ma, leading to the conclusion that M1 exerts a force of 30N on M2. Participants suggest drawing free body diagrams to clarify the forces at play. Understanding the relationship between the forces acting on both masses is crucial for solving the problem accurately.
JSmithDawg
Messages
9
Reaction score
0

Homework Statement


The illustration is not drawn to scale. M2 = 4 kg and M1=20kg. They're both on a frictionless surface. A 36N constant force is applied to M2. What's the force exerted by m1 on m2?
c46c31f0d2dc8a52d10ab9f7509a4415.jpg

Homework Equations


F=ma

The Attempt at a Solution


According to Newton's 3rd law, forces come in pairs. If there's 36N of force exerted on M2, the block should move and transfer the force onto M1. Since the surface is frictionless, I don't have to worry about any force being lost due to friction. Thus, 36N of force should be exerted onto M2 by M1. However, I know my logic is wrong, since the online quiz told me that the correct answer is 30N. How do I correctly approach this problem?
 
Physics news on Phys.org
JSmithDawg said:
According to Newton's 3rd law, forces come in pairs.
Yes, but as action and reaction. You can use that to determine the relationship between the forces the two masses exert on each other.
Consider the acceleration of the system. What force therefore acts on m1?
 
Since M1 and M2 move together, if a force of 36 N is applied to them, what is their acceleration?

Chet
 
Hi JSmithDawg.:)
Consider m1 and m2 as a system and find the acceleration of the system by using F=ma ,as Chestermiller said. Then draw free body diagrams of m1 and m2 separately. Can you find the magnitude of force acting on m1 due to m2? What is the relation between the acting on m1 by m2 and force acting on m2 by m1?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

Replies
17
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 21 ·
Replies
21
Views
2K
Replies
16
Views
8K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K