Force Exerted by Roads of Length x & Separation x - Physics Problem

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Homework Help Overview

The problem involves calculating the gravitational force exerted between two roads of equal length and separation, each with specified masses. The original poster attempts to apply the gravitational force equation but encounters difficulties with integration and variable representation.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the setup of the problem, including the representation of mass elements and the integration process. There are questions about the correct variables to use and the nature of the distance between the mass elements. Some participants suggest simplifying the problem by treating the roads as point masses.

Discussion Status

The discussion is ongoing, with various interpretations being explored. Some participants have provided guidance on how to approach the integration and variable assignment, while others express confusion and seek further clarification. There is no explicit consensus on the method to solve the problem.

Contextual Notes

Participants note that the original poster is in grade 10 and may not be familiar with advanced calculus concepts, which adds to the complexity of the discussion. There are also references to homework rules that prevent providing complete solutions.

  • #31
Good. Now that you know F(u) acting on a material point at x = u of mass m, let there be another rod between x = 2d and x = 3d, of mass m2. What is the net force?
 
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  • #32
Net force on point mass m? It will depend on the positions of m2 and m bcoz gravitational force is always attractive so there will be two cases ...please tell whether u > 3d...or d<u<2d
 
  • #33
Net force on the second rod from the first rod.

You know the location of the first rod: 0 ≤ x ≤ d. You know the location of the second rod: 2d ≤ x ≤ 3d.

You know the force from the first rod on a point at x = u.
 
  • #34
I solved it I came up with this answer F= (GMm ln(4/3))/d^2...please verify...
 
  • #35
I get the same answer. Very good!
 
  • #36
thank you very much...Are u sure that the answer is the same...?
 

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