- #1

dreamz25

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q) A force F acts on a block of mass m placed on a horizontal smooth surface at an angle Θ with horizontal. Then

(A) If F sinΘ < mg then a = (F + mg) / m

(B) Acceleration = FcosΘ/m where, F > mg cosecΘ

(C) Acceleration = F/m if FsinΘ > mg

(D) If F SinΘ > mg then a = (F + mg) / m

my work

--------

on drawing the F.B.D we we get..

clearly there will be linear and vertical acceleration as well...

Now if F sinΘ > mg then the Normal force will be 0

=> F sinΘ - mg = ma

_{y}---- (i)

and, F cosΘ = ma

_{x}------ (ii)

Adding the two eqns. we get,

F sinΘ + F cosΘ - mg = m (a

_{x}+ a

_{y})

or, a

_{x}+ a

_{y}= (F - mg) / m

but the correct option is d.

couldn't represent vectors with their notations so please understand

it urselves.

Am i wrong? if yes then where and why?

Thanks in advance...!