Force - gondola car suspended between 2 cables

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SUMMARY

The discussion focuses on calculating the tension in cables supporting a gondola car weighing 789 kg, suspended at a 90° angle. The tension in each cable is equal to the weight of the car, which is determined using the formula T = mg, where T is tension, m is mass, and g is the acceleration due to gravity (9.81 m/s²). Therefore, the tension in each cable is 7728.09 N, as the weight of the car directly translates to the tension due to the vertical suspension.

PREREQUISITES
  • Understanding of basic physics concepts, specifically forces and tension.
  • Familiarity with Newton's laws of motion.
  • Knowledge of gravitational acceleration (9.81 m/s²).
  • Ability to perform basic calculations involving mass and weight.
NEXT STEPS
  • Study the principles of static equilibrium in physics.
  • Learn about vector components of forces in two-dimensional systems.
  • Explore real-world applications of tension in engineering structures.
  • Investigate the effects of angles on tension in cable systems.
USEFUL FOR

This discussion is beneficial for physics students, engineering students, and professionals involved in structural design and analysis, particularly those interested in cable systems and tension calculations.

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Homework Statement



A car weighing 789 kg hang at an angle of 90°. What is the tension in each cable?

The Attempt at a Solution



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