Force in an elevator during acceleration

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SUMMARY

The discussion revolves around calculating the scale reading of a woman standing in an accelerating elevator. Given her mass of 60.0 kg and the combined mass of the elevator and scale at 815 kg, the hoisting cable exerts a force of 9410 N during upward acceleration. The correct approach involves applying Newton's second law, F = ma, to determine the effective acceleration and subsequently the force exerted on the scale. The final scale reading reflects the increased apparent weight due to the upward acceleration.

PREREQUISITES
  • Understanding of Newton's second law (F = ma)
  • Basic knowledge of forces and acceleration
  • Concept of apparent weight in non-inertial frames
  • Ability to perform calculations involving mass and force
NEXT STEPS
  • Study the effects of acceleration on apparent weight in different scenarios
  • Learn about forces in non-inertial reference frames
  • Explore the implications of varying acceleration on scale readings
  • Investigate real-world applications of Newton's laws in elevators and other moving systems
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Students studying physics, particularly those focusing on mechanics and forces, as well as educators seeking to explain concepts of acceleration and apparent weight in practical scenarios.

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Homework Statement



A woman stands on a scale in a moving elevator. Her mass is 60.0 kg, and the combined mass of the elevator and scale is an additional 815 kg. Starting from rest, the elevator accelerated upward. During the acceleration, the hoisting cable applies a force of 9410 N. What does the scale read during the acceleration?

Homework Equations



F= ma

The Attempt at a Solution



9410 = 9.8(815 + 60) * a

I think the above equation is right, but not 100% on that. I can't figure out how to do the rest of this problem. Any help will be greatly appreciated. Thanks in advance!
 
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I believe you should solve the equation like this

F = m*a

since you are accelerating upwards a > 9.8m/s^2

Using the given force and the given weight you can find the "new" acceleration.

Using that acceleration you can find the force on the scale caused by the women.

Then using that force you can determine what her weight will show, (since you can assume the scale reads weights based off a = 9.8m/s^2, so a larger force will result in a larger weight)

Also, when you look at your above equation it is in the form F = m*a^2
 
Last edited:
Awesome! Thanks for helping me out!
 

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