Solving Elevator Problem Homework Statement

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Homework Help Overview

The discussion revolves around a physics problem involving a woman standing on a scale in a moving elevator. The scenario includes her mass, the mass of the elevator, and the force applied by the hoisting cable during upward acceleration.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants attempt to calculate the apparent weight using the net force and acceleration. There are discussions about the correct interpretation of mass and weight, as well as the units involved in the calculations.

Discussion Status

Participants are exploring various interpretations of the problem, questioning the values used for mass and weight, and discussing the implications of their calculations. Some guidance has been offered regarding the correct units and the significance of the mass of the elevator versus the woman.

Contextual Notes

There is confusion regarding the mass of the elevator and the scale, with some participants suggesting different values and questioning the assumptions made in the calculations. The original problem does not explicitly state the mass of the elevator, leading to varied interpretations.

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Homework Statement


A woman stands on a scale in a moving elevator. Her mass is 50kg and the combined mass of the elevator accelerates upward. During the acceleration , the hoisting cable applies a force of 9350N. What does the scale read during the acceleration ?


Homework Equations


F net= T-MG= Ma
Apparent weight = mg(a/g+1)

The Attempt at a Solution


First we find a and the plug in the a in the apparent weight and we find the scale reading
first attempt: 9530-(50+815) = (815+50)a
and a= 1.22m/s^2
and the apparent weight = 9532N
 
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Anthonyphy2013 said:

Homework Statement


A woman stands on a scale in a moving elevator. Her mass is 50kg and the combined mass of the elevator accelerates upward. During the acceleration , the hoisting cable applies a force of 9350N. What does the scale read during the acceleration ?


Homework Equations


F net= T-MG= Ma
Apparent weight = mg(a/g+1)

The Attempt at a Solution


First we find a and the plug in the a in the apparent weight and we find the scale reading
first attempt: 9530-(50+815) = (815+50)a

You are mixing up Newtons with kg in this equation.
Your problem doesn't state it but I gather the mass of the elevator is 815 kg.
 
Where does the number 815 come from?
Please work with units, it is easier to spot errors that way. For example, you cannot subtract 50kg from 9350N, that does not make sense.

and the apparent weight = 9532N
It would be impossible to stand on a scale in that case (that is the weight of a car), the result cannot be true.
 
815 comes from the combined mass of the elevator and the scale .
9530N-(865*9.8)N=(865)a
a=1.22 m/s2
Apparent weight=N=Mg(a/g+1)
=(865*9.8)(1.22/9.8 + 1)
9532.3N
Is that corrected ?
 
Last edited:
Anthonyphy2013 said:
815 comes from the combined mass of the elevator and the scale .
You mean 815 is the mass of the elevator, I think.
9530N-(865*9.8)N=(865)a
a=1.22 m/s2
That is finally correct.
Apparent weight=N=Mg(a/g+1)
=(865*9.8)(1.22/9.8 + 1)
9532.3N
Is that corrected ?

No. She's not going to weigh much more than at rest. And the scale reads in kg, not N.
So the answer is not much more than 50 kg.
 
Anthonyphy2013 said:
Apparent weight=N=Mg(a/g+1)
=(865*9.8)(1.22/9.8 + 1)
865? Isn't that going to give you the apparent weight of the elevator+passenger?
 
haruspex said:
865? Isn't that going to give you the apparent weight of the elevator+passenger?

so you mean the mass is 50 not 865( 815+50) ?
 
Anthonyphy2013 said:
so you mean the mass is 50 not 865( 815+50) ?

Yes. You're not measuring the weight of the elevator, right?
 

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