You have an object of mass 6.154 kg on the surface of the moon. What force is required to propel the object vertically to a height of 100m?
acceleration due to gravity on the moon (g): 1.625 m/s^2
y = (v^2 - v0^2) / (2*g)
y: vertical displacement
v: velocity at displacement
v0: initial velocity
g: acceleration due to gravity
y = v0*t - (1/2)*g*t^2
t: time of flight
KE = (1/2)*m*v^2
KE: Kinetic energy
The Attempt at a Solution
Weight of object on the moon is 6.154kg * 1.625 m/s^2 = 10 N.
Using the first equation above with v = 0 (apex of flight) and solving for v0, I find that the required initial velocity is 18.03 m/s.
The second equation gives a flight time of 22.19 seconds--11.095 seconds to apex and 11.095 seconds back to the surface.
The third equation yields a required kinetic energy needed of 988.25 J which is the same as the work required by the propulsion system because the object is initially at rest.
And this is where I get stuck. What equation do I use next? Power? How do I get the propulsive force required?