Force of friction on two blocks

Click For Summary
SUMMARY

The discussion centers on calculating the acceleration and the force of friction between two blocks, A and B, with given masses of 5.00 kg and 10.0 kg, respectively. A pulling force of 200 N is applied, and the coefficient of kinetic friction between block B and the tabletop is 0.800. The acceleration of the system is determined to be 5.5 m/s². The force of friction between the blocks is calculated using the formula for frictional force, which is the product of the coefficient of friction and the normal force, leading to a required frictional force of approximately 173 N.

PREREQUISITES
  • Understanding of Newton's Second Law of Motion
  • Knowledge of frictional force calculations
  • Familiarity with mass and acceleration concepts
  • Basic algebra for solving equations
NEXT STEPS
  • Study the principles of Newton's Laws of Motion
  • Learn about calculating frictional forces in different scenarios
  • Explore the relationship between mass, acceleration, and net force
  • Investigate the effects of different coefficients of friction on motion
USEFUL FOR

Students in physics, particularly those studying mechanics, as well as educators and anyone involved in teaching or learning about forces and motion in a practical context.

afg_91320
Messages
39
Reaction score
0

Homework Statement


Two blocks, A and B remain stuck together as they are pulled to the right by a force F = 200 N to the horizontal right. B is on a rough horizontal tabletop (coefficiant of kinetic friction is .800)

a) what is the acceleraton of the system
b) what is the force of friction between the two objects?

pic below:
11qs8ef.jpg


mass of A = 5.00 kg
mass of B = 10.0 kg


Homework Equations


m A = 5.00 kg
m B = 10.0 kg
F = 200N
kinetic friction = 0.800


The Attempt at a Solution


a) i already found the acceleration to be 5.5 m/s^2

b) this is where i am STUCK. all i have is the coeff of the friction which is .800
what do i do with it??
 
Physics news on Phys.org
Where is the force directed? On the bottom block?

But that aside, the force of acceleration is just its mass times the acceleration isn't it? And since it's not sliding it must be supplied by friction if the force isn't acting on it directly.
 
^the force is directed right towards the middle of A and B coming from the right side.
so mass times accl will give me the force?
that would be 82.5 and i know that is incorrect because the answer for b should be around 173 N
 

Similar threads

Replies
13
Views
3K
Replies
6
Views
1K
  • · Replies 21 ·
Replies
21
Views
2K
Replies
10
Views
1K
Replies
16
Views
3K
Replies
7
Views
2K
Replies
18
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 23 ·
Replies
23
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K