Force on a Magnet Moving through a Wire Loop

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SUMMARY

The force acting on a magnetic dipole falling through a loop of wire can be derived using the equations of electromagnetism. The voltage induced in the loop is given by V = -d(BA)/dt, where B is the magnetic field and A is the area of the loop. The total voltage in the circuit can be expressed as V = I*R_circuit + L*dI/dt, indicating that the resistance of the wire loop plays a crucial role in determining the induced current. The potential energy U is defined as U = -m*B, and the force F can be calculated using F = -dU/dx, which highlights the complexity of the relationship between the magnetic dipole and the wire loop.

PREREQUISITES
  • Understanding of electromagnetic induction principles
  • Familiarity with the concept of magnetic dipoles
  • Knowledge of circuit theory, specifically Ohm's Law
  • Basic calculus for differentiation and integration
NEXT STEPS
  • Study Faraday's Law of Electromagnetic Induction
  • Learn about Lenz's Law and its implications on induced currents
  • Explore the dynamics of magnetic dipoles in varying magnetic fields
  • Investigate the effects of resistance on induced electromotive force (EMF)
USEFUL FOR

Physics students, electrical engineers, and anyone interested in the principles of electromagnetism and their applications in circuits.

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Homework Statement



What is the force acting on a magnetic dipole that falls through a loop of wire?

Any sort of answer, exact, approximate or a reference to a source that covers this would be excellent. I haven't been able to find much of anything on this problem.

Homework Equations


The Attempt at a Solution



Start with:
V=-d(BA)/dt
V=I*R_circuit + L*dI/dt
B-field of a loop of wire
U=-m*B
F=-dU/dx (and this is hugely messy and nonlinear)
 
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For openers, I believe it depends on the resistance of the wire loop.
 

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