Force on an electron between two parallel plates

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SUMMARY

The force on an electron between two parallel plates separated by 10.0 cm with a potential difference of 500.0 V is calculated using the formula F = Vq / r. The correct calculation yields a force of 8 x 10-18 N, not 8 x 10-16 N as initially computed. The error in the initial calculation stemmed from a miscalculation of the electron charge and the distance between the plates.

PREREQUISITES
  • Understanding of electric fields and forces
  • Familiarity with the concept of potential difference
  • Knowledge of the charge of an electron (approximately 1.6 x 10-19 C)
  • Basic algebra for manipulating equations
NEXT STEPS
  • Review the derivation of electric field strength (E) between parallel plates
  • Learn about the relationship between electric potential (V) and electric field (E)
  • Study the effects of distance on force calculations in electrostatics
  • Explore common mistakes in electrostatic force calculations
USEFUL FOR

Students studying physics, particularly those focusing on electromagnetism, and educators looking to clarify concepts related to electric forces and potential differences.

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Homework Statement


Two parallel plates are separated by 10.0cm and a potential difference of 500.0V is maintained between them. What is the force on an electron between the plates?


Homework Equations





The Attempt at a Solution


E = F / q = kQ / r2
V = kQ / r = Er = Fr / q
F = Vq / r = 500.0 * e / 0.100 = 8 * 10-16

The actual answer is 8 * 10-18
Where did my calculation go wrong?
 
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I got the same answer as yourself.Don't forget the units.
 

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