At what angle will the electrons in the image leave the uniform electric field at the end of the parallel plates (point P) ? Assume the plates are .049 m long, E = 5x10^3 N/C and v0 = 1x10^7 m/s. Ignore fringing of the field.
E = kQ/r^2
The Attempt at a Solution
I am having difficulty figuring out how to get started. I know the equation for the motion of the electron is
y= -(eEx^2)/(2mv0^2) but I don't know if this helps me. I think they want the angle the path of the electron makes with the x axis, but I am not sure. Can someone get me started or give me a hint on how to relate the angle to everything else please?