(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A roller-coaster car has a mass of 500 kg when fully loaded with passengers. At the bottom of a circular dip of radius 40 m (as shown in the figure) the car has a speed of 16 m/s. What is the magnitude of the force of the track on the car at the bottom of the dip?

2. Relevant equations

Force on an object traveling in a circle perpendicular to the force of gravity is centripetal acceleration plus acceleration due to gravity times the mass of the object.... i think

3. The attempt at a solution

16 meters per sec squared divided by 40 meters times 500 kg ...... plus 500 kg times 9.8 meters per second squared = 8.1 kN ... right?

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# Homework Help: Force on coaster = ma(c) + ma(g) ?

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