Is the Roller Coaster Speed Calculation Correct?

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Homework Help Overview

The problem involves calculating the speed of a roller coaster at the bottom of a dip, where a passenger experiences an upward force that is three times her weight. The context is centered around the application of Newton's laws and the forces acting on the passenger.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the forces acting on the passenger, questioning the original poster's approach to identifying the net force. There is a focus on the relationship between the normal force and gravitational force.

Discussion Status

Participants are actively engaging in clarifying the forces involved and the correct application of Newton's laws. There is acknowledgment of the need to consider both the normal force and weight in the analysis, indicating a productive direction in the discussion.

Contextual Notes

There is a specific mention of the forces acting on the passenger, with the upward force being three times her weight, which is a key assumption in the problem setup.

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Homework Statement



A roller coaster at an amusement park has a dip that bottoms out in a vertical circle of radius r. A passenger feels the seat of the car pushing upward on her with a force equal to 3.0 times her weight as she goes through the dip.If r=25m, how fast is the roller coaster traveling at the bottom of the dip?

The Attempt at a Solution



F=mv*2/r
3Mg=mv*2/r
3g=v*2/25
V=27.12ms-1
Is this the correct solution?
 
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No, you must look at the net force acting on the passenger before applying Newton's laws. You only looked at one of the forces. What is the other?
 
PhanthomJay said:
No, you must look at the net force acting on the passenger before applying Newton's laws. You only looked at one of the forces. What is the other?
But, isn't the magnitude of the force is equal to 3 times of the weight...where w is equal to mg
( base on the question)
 
the question does say that the force due to the seat is 3 times her weight. But she does have another force on her (as Phanthomjay said).
 
So, the net force is N-mg...where N(upward force) is equal to 3 times of mg(weight)...?
 
Thanks...
 

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