What Is the Magnitude of B for a Current-Carrying Wire in a Magnetic Field?

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SUMMARY

The magnitude of the magnetic field B for a current-carrying wire can be calculated using the formula F = BILsin(θ). In the discussed scenario, a straight wire of length 0.90 meters carrying a current of 60 A at an angle of 45 degrees experiences a force of 2.0 N. By substituting the known values into the equation, B is determined to be 0.37 T. The initial attempt incorrectly applied the formula for a wire perpendicular to the magnetic field.

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Ry122
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A straight wire of length 90 cm carries a current of 60 A and makes an angle of 45 degrees with a uniform magnetic field. If the force on the wire is 2.0 N what is the magnitude of B.

my attempt:
F=BIL
2=B(6)(.90)
B=.37
What am i doing wrong?
 
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F=BIL is assuming the conductor is at 90 degrees to the magnetic field.

if it is at an angle \theta, then the formula becomes F=BILsin\theta
 

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