Force problem with non-massless rope

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Homework Help Overview

The problem involves a block of mass M being pulled along a frictionless surface by a rope of mass m, with a horizontal force F applied to one end of the rope. The discussion centers on the implications of the rope's mass on its behavior, particularly regarding sagging and tension.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the necessity of sagging due to the rope's mass and the effects of gravity. There are attempts to derive the acceleration and forces acting on the block and rope, but uncertainty arises regarding the tension in the rope at its midpoint.

Discussion Status

Some participants have provided insights into the sagging of the rope and the forces involved, while others are exploring the implications of these forces and questioning the assumptions made. There is no clear consensus on the approach to part (d), with suggestions for considering average forces and the effects of cutting the rope.

Contextual Notes

Participants note that this problem is unique due to the mass of the rope, which introduces complexities not typically encountered in similar problems. There is a recognition of the need to account for vertical forces acting on the rope.

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Homework Statement


A block of mass M is pulled along a horizontal frictionless surface by a rope of mass m. A horizontal force F is applied to one end of the rope. (a) Show that the rope must sag, even if only by an imperceptible amount. Then, assuming that the sag is negligible, find (b) the acceleration of rope and block, (c) the force on the block from the rope, and (d) the tension in the rope at its midpoint.

Homework Equations



F=ma

The Attempt at a Solution



For (a), it is because the rope has mass so gravity acts on it. Since no other vertical force acts on the rope, it's net force is downwards and therefore must sag.

For (b): From force = mass * acceleration:

[tex]a = \dfrac{F}{m+M}[/tex]

For (c), the pull of the rope is the only force acting on the block. It is also accelerating with the block:

[tex]F = M\cdot a = \dfrac{M\cdot F}{m+M}[/tex]

So far, everything makes sense to me. However, I am not sure how to approach part (d) because this is the first problem where the rope has mass, so I don't know how to deal with it. Can anyone help?
 
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azure kitsune said:

Homework Statement


A block of mass M is pulled along a horizontal frictionless surface by a rope of mass m. A horizontal force F is applied to one end of the rope. (a) Show that the rope must sag, even if only by an imperceptible amount. Then, assuming that the sag is negligible, find (b) the acceleration of rope and block, (c) the force on the block from the rope, and (d) the tension in the rope at its midpoint.

Homework Equations



F=ma

The Attempt at a Solution



For (a), it is because the rope has mass so gravity acts on it. Since no other vertical force acts on the rope, it's net force is downwards and therefore must sag.

For (b): From force = mass * acceleration:

[tex]a = \dfrac{F}{m+M}[/tex]

For (c), the pull of the rope is the only force acting on the block. It is also accelerating with the block:

[tex]F = M\cdot a = \dfrac{M\cdot F}{m+M}[/tex]

So far, everything makes sense to me. However, I am not sure how to approach part (d) because this is the first problem where the rope has mass, so I don't know how to deal with it. Can anyone help?

Your answer for a) isn't quite complete. Because there is a vertical component down from weight, there must be corresponding components of the tension in the positive y direction to offset it, or it would be in motion downward.

For d) you have answered what the Force is pulling from the end of the rope and you have answered what the Force from the rope pulling the block, so ... what do you figure it is half way in between?
 
Would this be a more complete answer for (a)?:

Assume that the rope is perfectly horizontal. However, gravity is acting on the rope, yet it is not moving downwards. Therefore there must be an corresponding upward force acting against gravity. But the rope is perfectly horizontal, so there is no upward force from the tension of the rope, and there are no other vertical forces acting on the rope. Contradiction?

For (d), I'm guessing it's the average? But I can't think of any reason using physics principles.
 
azure kitsune said:
Would this be a more complete answer for (a)?:

Assume that the rope is perfectly horizontal. However, gravity is acting on the rope, yet it is not moving downwards. Therefore there must be an corresponding upward force acting against gravity. But the rope is perfectly horizontal, so there is no upward force from the tension of the rope, and there are no other vertical forces acting on the rope. Contradiction?

For (d), I'm guessing it's the average? But I can't think of any reason using physics principles.

That answer shows a better understanding for a)

For d) think about if you had cut the cable in half and connected it back together with a small linkage. What force would the half alone exert on the other half and the block?
 

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