Force related to distance question

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SUMMARY

The discussion focuses on calculating the total distance traveled by an object moving up a 15-degree incline under the influence of a time-dependent force. The user has established a relationship between work and energy, utilizing the equation U = ∫F ds = mg sin(15)s + (mV₂²)/2 - (mV₁²)/2. The challenge lies in integrating the force function F(t) to derive acceleration a(t), which subsequently leads to velocity v(t) and distance d(t). The user seeks clarification on how to proceed with the integration given the complexities of the force function.

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  • Familiarity with calculus, particularly integration techniques.
  • Knowledge of kinematics, including initial and final velocity concepts.
  • Experience with forces acting on inclined planes.
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Homework Statement


So I have worked through most of the problem and what I have so far is correct. Basically, I have force as a function of time which, when exerted on an object, moves the object up a 15 degree slant. Given two points in times, my question reduces to finding the total distance traveled within this time period. It should be known I have initial and final velocities.

Homework Equations


work/energy seems useful here [itex]U=\Delta V_G + \Delta T[/itex]

i don't think i need impulse, or namely [itex]\int \sum F dt= \Delta G[/itex] as this deals explicitly with time, which I have already used to get the force function (though I could be wrong)

The Attempt at a Solution


I was thinking [itex]U=\int F ds = m g sin(15) s + m {{V_2}^2}/2 - m {{V_1}^2}/2[/itex] where [itex]s[/itex] is the distance traveled I am looking for and the force function [itex]F[/itex] is changed to only account for forces other than gravity (since the [itex]\Delta V_G[/itex] term accounts for potential gravity.

but then, since [itex]F[/itex] is a function of time, I'm not sure how to proceed (if you need the force function I can give it, but it's kind of long)

I know both initial and final velocities [itex]V_1 , V_2[/itex]

Any ideas would be helpful! Thanks!
 
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I would think that given F(t), and the mass, you would integrate a(t) to find v(t) and then again to find d(t) distance a function of time. When you integrate a(t) you have the initial velocity given. Does the force act parallel to the plane?
 

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