Force required down an incline.

[Gheret]

Homework Statement

The co-efficient of kinetic friction for a 22kg bobsled on a track is 0.10. What force is required to push it down a 6 degree incline and achieve a speed of 60km/h at the end of 75m.

Homework Equations

Ffr=uFn
v^2=2a(x)
F=ma

The Attempt at a Solution

(65/3.6)^2=2a(75)
a=2.17ms^-2

F=ma
F=(22)(2.17)
F=47.8

Ffr=uFn=(0.10)(22)(9.8)sin6=21N
But then I am not sure what to do next?

 

[Gheret]

I think I may have been overthinking this problem
The sled is at rest so Ffr=mgcos
So force required is
(60/3.6)^2=2a(75)
a=1.85ms^-2
F=22x1.85=40.7N
Which is the answer in the book.
Can't believe I worked on this problem for about an hour.