Force to lift a chain: Conservative or not?

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Homework Help Overview

The problem involves lifting a chain with a linear mass density at a constant velocity and determining the force required as a function of height. The discussion centers around the nature of the force involved and whether it can be classified as conservative, particularly in relation to the changing mass of the chain during the lifting process.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between potential energy and the force required to lift the chain, questioning the implications of the chain's mass distribution and whether the force can be considered conservative.

Discussion Status

Participants are examining the definitions of conservative forces and the conditions under which the work done is zero on a closed path. Some guidance has been offered regarding the nature of the applied force versus gravitational force, and the reasoning behind lifting the chain at constant speed is being discussed.

Contextual Notes

There is a focus on the implications of the chain's mass being non-constant as it is lifted, and the discussion includes considerations of how this affects the classification of the force as conservative. The initial conditions of the chain's position are also clarified.

AJKing
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Homework Statement



You are lifting a chain straight up at a constant velocity v_0. The chain has a linear mass density λ. What is the force required to lift the chain as a function of height?

The Attempt at a Solution



U = mgh = λygh

The height in the potential energy is the same as the potential energy at the center of mass

h = y/2

U = λgy^2/2

This is a conservative potential energy in one dimension

F = -∂U/∂y= -λgy

Is this correct?

Can conservative forces consider objects of non-constant mass as I've done?
 
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Is the chain initially lying on the ground then.

Per your question:
By definition of a conservative force, the work should be zero on a closed path right?
So check.
 
Simon Bridge said:
Is the chain initially lying on the ground then.

Per your question:
By definition of a conservative force, the work should be zero on a closed path right?
So check.

Yes, it's on the ground.

Right, the work done on the object should be zero about a closed path. Regardless of the fact that my work is not zero.
The work done on this chain will certainly be zero about any closed path.
The change in mass does not matter.

Then I suppose my force is conservative and that my equation is correct in the case that the chain doesn't leave the surface. As soon as it does, I've got to rewrite to:

F = -λLg

which is constant.

Is that all correct?
 
The applied force here is not really from a field though is it?

Technically it is gravity that is the conservative force - since it can be described as the gradient of a potential function. Your applied force only exists at a point - it (or rather, whatever is applying the force) is the thing doing the work.

But your math looks fine from here.

To check this sort of thing all you need is to check the reasoning - to lift at constant speed, the applied force has to be equal to gravity. Presumably it was briefly larger than gravity at some earlier stage in order to accelerate to the constant speed.

This is one would modify the model to allow for finite sized links in the chain.
 

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