Force & Torque Homework: 10kg Plank on Wall/Floor

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Homework Help Overview

The problem involves a 10 kg plank leaning against a frictionless wall and floor at a 60-degree angle. Participants are tasked with determining the normal forces at the wall and floor, the tension in a connecting rope, and demonstrating that the net torque is zero at a specific pivot point.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss using dynamics and torque to find the normal forces and tension. There are attempts to set up torque equations based on different pivot points, with some questioning the adequacy of information available to solve the problem.

Discussion Status

Participants are exploring various approaches to the problem, including different pivot points for torque calculations. Some have provided equations based on their reasoning, while others express uncertainty about the information needed to proceed effectively.

Contextual Notes

There is mention of missing information, such as the length of the plank and the tension force, which may impact the ability to solve the problem completely. Participants are also navigating the constraints of homework rules regarding solution completeness.

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Homework Statement


A 10 kg plank leans against a frictionless wall and floor at an angle of 60 degrees with the horizontal. A horizontal rope connects the center of mass of this uniform plank with the wall.
a- Use dynamics to find the normal force between the floor and the plank.
b- Find the normal force between the wall and the plank.
c- Determine the tension in the rope.
d- Show the net torque is zero when the pivot is located where the plank meets the wall.


Homework Equations



torque = Fsin(phi) radius

The Attempt at a Solution


a- normal floor = weight = 10kg (9.8) = 98 N
b- Using torque, I end up with -56.6.

-torque of normal floor + torque of normal wall = 0
98 N (sin 210) length/2 = normal wall (sin 120) length /2

normal wall = -56.6
What am I doing wrong?
 
Last edited:
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veronicak5678 said:

Homework Statement


A 10 kg plank leans against a frictionless wall and floor at an angle of 60 degrees with the horizontal. A horizontal rope connects the center of mass of this uniform plank with the wall.
a- Use dynamics to find the normal force between the floor and the plank.
b- Find the normal force between the wall and the plank.
c- Determine the tension in the rope.
d- Show the net torque is zero when the pivot is located where the plank meets the wall.


Homework Equations



torque = Fsin(phi) radius

The Attempt at a Solution


a- normal floor = weight = 10kg (9.8) = 98 N
b- Using torque, I end up with -56.6.

-torque of normal floor + torque of normal wall = 0
98 N (sin 210) length/2 = normal wall (sin 120) length /2

normal wall = -56.6
What am I doing wrong?

Using the point where the plank rests on the ground as the point of rotation, a torque due to tension and one due to gravity act in the negative direction, both of which are negated by a normal force imposed upon the plank by the wall in the clockwise direction. Does this help?
 
If I use that as the rotation spot, I don't think I will have enough info to solve. I don't know the tension force or the length of the plank. I was using the center as the pivot to avoid lookig at tension and weight.
 
I tried using that spot and this is what i came up with:

torque tension + torque weight - torque normal floor = 0
56.6 N * sin 240 * length/2 + 98 N * sin 150 * length/2 - 98 N * sin 210 * length = 0

But this equation leaves me with 49N * length, not 0.
 

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