Forces and Angles Above The Horizontal (2 prob.)

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SUMMARY

The discussion focuses on solving two physics problems involving forces and angles. In the first problem, a sled is pulled with a force of 80 N at an angle of 53 degrees, resulting in a friction force of 48 N, confirming option C as the correct answer. The second problem involves a trapeze artist weighing 800 N, where the horizontal force applied by a partner is calculated to be 924 N, confirming option A as the correct answer. Key concepts include resolving forces into components and understanding static equilibrium.

PREREQUISITES
  • Understanding of force resolution into components
  • Knowledge of static equilibrium principles
  • Familiarity with trigonometric functions (sine, cosine)
  • Basic physics concepts regarding forces and motion
NEXT STEPS
  • Study force resolution techniques in physics problems
  • Learn about static equilibrium and its applications
  • Explore trigonometric functions in the context of physics
  • Practice solving problems involving angles and forces
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Students studying physics, educators teaching mechanics, and anyone interested in understanding forces and angles in real-world applications.

rwishka
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Homework Statement



1. A sled is pulled at a constant velocity across a horizontal snow surface. If a force of 8.0 x 10^1 N is being applied to the sled rope at an angle of 53 degrees to the ground, what is the force of friction between the sled and the snow?

A. 83 N
B. 64 N
C. 48 N
D. 42 N

2. A trapeze artist weighs 8.00x10^2 N. The artist is momentarily held to one side of a swing by a partner so that both of the swing ropes are at an angle of 30 degrees with the vertical. In such a condition of static equilibrium, what is the horizontal force being applied by the partner?

A. 924 N
B. 433 N
C. 196 N
D. 610 N


Homework Equations


I don't know any formulas to use for this.

The Attempt at a Solution



I'm sorry, but if I knew what formula to use, I could probably do it. I can't find any formulas that include angles in the section.
 
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Try drawing diagrams, and resolving forces into components.

For the first question, since the velocity is constant, what can you say about the resultant horizontal force?

For the second question, again, what can you say about the resultant force?
 
So, would it be F=80(cos 53 degrees). So F=48 N. Answer C, then?

For the second question, I did 800 = cos 30 degrees (F), so F = 924 N. Answer A.

Thank you SO much! :biggrin: :biggrin:
 

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