1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Forces and Newton's Laws of a train

  1. Jul 29, 2009 #1
    1. The problem statement, all variables and given/known data
    A train consists of of 50 cars, each of which has a mass of 6800 kg. The train's acceleration = 0.08 m/s(squared). Ignore friction and determine the tension in the coupling (a) between the 30th and 31st cars and (b) between the 49th and 50th cars.

    2. Relevant equations
    Net Force = Tension = mass * acceleration

    3. The attempt at a solution
    Used the equation above I came to:
    16320 N for part (a) and
    26656 N for part (b).
    My problem is, I'm thinking those answers are supposed to be divided by some amount since there are couplings between each car.
     
  2. jcsd
  3. Jul 30, 2009 #2

    alphysicist

    User Avatar
    Homework Helper

    Hi Cheddar,

    Those results don't sound right to me; how did you get those numbers? (Notice that in this problem the coupling in part a is responsible for pulling many more cars than the coupling in part b.)
     
  4. Jul 30, 2009 #3
    Have you tried drawing free body force diagrams for the two cars?
     
  5. Jul 30, 2009 #4
    This is what I did.:
    Each car has a mass of 6800 kg.
    Part (a) 6800 kg * 30 cars = 16320 N
    Part (b) 6800 kg * 49 cars = 26656 N
     
  6. Jul 30, 2009 #5
    I agree with your answers. Although, your equations above are confusing because you didn't show that you multiplied by the acceleration 0.08, but the numbers you wrote imply that you did muliply it.

    Consider the last car on the train. It is pulling nothing. It is being pulled by the next to last car. So the coupler must be pulling only the mass of the last car multiplied by the acceleration. Now the third car is pulling on the two behind it. So it's coupler is pulling at 2*mass*accel, etc, etc all the way up to the engine which is providing the pull for the entire train of cars.
     
  7. Jul 30, 2009 #6

    alphysicist

    User Avatar
    Homework Helper

    Okay, that's the right idea, but I think they mean the 1st car is the car right behind the engine, and the 50th car is the last car.

    So that in part a, the coupling is pulling twenty cars, and in part b it is only pulling one car.
     
  8. Jul 30, 2009 #7

    tms

    User Avatar

    Your second paragraph contradicts your first. If the second is correct (and it is), then the original answers must be wrong, because the tension in the last coupling must be less than that in any other coupling.
     
  9. Jul 30, 2009 #8
    I don't think it's a contradiction because as alphy pointed out I was counting the cars from the back because that made Cheddar's answers correct. I was assuming that his actual problem drawing must have been numbered that way. However, if you number the cars the other way, then yes the answer changes.
     
  10. Jul 30, 2009 #9

    tms

    User Avatar

    Sorry; I didn't realize that.
     
  11. Jul 30, 2009 #10
    No problem. Both the OP and I should have been specific on our counting reference. Sorry for the confusion.
     
  12. Jul 30, 2009 #11
    Thanks everyone. I was counting the opposite way I guess. There is no picture or explaination as to the numbering of the cars so I guess we really have no idea which answers are correct...
    I'm using the one with the first car being behind the engine though. I think it makes more since. Thanks again.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Forces and Newton's Laws of a train
Loading...