Forces on a pressurized tin can of beans

  • Thread starter Thread starter billybomb
  • Start date Start date
  • Tags Tags
    Forces
Click For Summary

Discussion Overview

The discussion revolves around determining the force a pressurized tin can of beans can support before failing. Participants explore various theoretical approaches, including short column buckling, axial and hoop stress for thin-walled vessels, and the effects of internal pressure. The conversation includes numerical calculations and assumptions about the can's dimensions and material properties.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • The original poster (OP) seeks help calculating the force a tin can can withstand, providing dimensions and material properties, and questions whether internal pressure is equivalent to atmospheric pressure.
  • One participant notes that the thickness of the can's metal is crucial for making any estimations and mentions the importance of the can's structural design, such as whether the sides are straight or corrugated.
  • The OP later provides the thickness of the can and mentions that the sides are corrugated, stating they calculated a force of 53683.1N using axial stress for thin-walled cylinders.
  • Another participant comments on the internal pressure of the can, suggesting that if it is 30 psi, the contents may be spoiled, as vacuum packing is typical for canned goods.
  • A different participant questions the implications of vacuum packing, suggesting it could lead to lateral deformation of the can.
  • Another response emphasizes the strength of the can, arguing that even under vacuum conditions, atmospheric pressure can exert significant force on the can's structure.
  • One participant humorously reframes the concept of atmospheric pressure, suggesting that it is substantial when considered in terms of force per square foot, and speculates on the potential for a person to stand on two cans without crushing them.

Areas of Agreement / Disagreement

Participants express differing views on the implications of internal pressure, the structural integrity of the can, and the calculations involved. There is no consensus on the final force the can can support, and the discussion remains unresolved.

Contextual Notes

The discussion includes assumptions about the can's material properties, internal pressure, and structural design, which may affect the calculations and conclusions drawn by participants.

billybomb
Messages
9
Reaction score
0
Hi

So I'm trying to find out how much force a tin can, can support before failing. The can will be stood up as it should be with a force applied over the top across the area of the can.

I've tried the process of short column buckling to no avail.

I've also tried axial and hoop stress for thin walled pressurized vessels.

I keep getting silly numbers and am now completely lost.

Also, would you assume that pressure inside the can is the same as atmospheric?

So here are the numbers:

Length = 109mm
Diameter = 74mm
Assumed yield stress of 590n/mm^2
Atmospheric pressure = 0.101325n/mm^2

Any direction or help would put my mind at ease, thanks

I've found http://ntrs.nasa.gov/archive/nasa/casi.ntrs.nasa.gov/19690013955_1969013955.pdf
Is page 14 the part I am look for?

Thanks again.
 
Last edited:
Engineering news on Phys.org
Without knowing the thickness of metal in the can, you won't be able to even hazard a guess. It is also important to know if the sides of the can are rolled straight or if they might have any corrugations.
 
Yea, sorry forgot to include that...

Thickness = 0.4mm

The sides are corrugated, but I am just after the basic theory of the crushing force needed.

I've got 53683.1N using Axial stress for thin walled cylinders

Also tried a basic calculation of Stress = F/A + Pressure*pi*r^2 and rearrange for F

I've also found that the internal pressure of a can of beans is 30psi or 206842.72 N/m^2

Thanks a lot
 
Last edited:
No ideas? :<
 
If your can of beans has an internal pressure of 30 psi, I suspect that the beans have spoiled. Usually, canned food is vacuum packed to eliminate any air inside the can which might promote spoilage of the contents. Carbonated beverages obviously are an exception, as the internal pressure inside the can provides resistance to collapse of the can.
 
If the can is vacuum packed, wouldn't that mean the tin has negative internal pressure and would deform laterally?
 
Not necessarily. Although cans are not infinitely strong, they do have some strength. That's why the thickness of the metal and what kind of corrugations are important in trying to determine the strength of the can. After all, even if a perfect vacuum forms inside the can, the maximum atmospheric pressure is still only about 15 psi.
 
SteamKing said:
After all, even if a perfect vacuum forms inside the can, the maximum atmospheric pressure is still only about 15 psi.

Be careful with that word "only". I prefer to think of it as nearly 1 ton per square foot, which doesn't sound quite so puny!

With the OP's can dimensions, 15 psi is about 100 pounds force on each end of the can. Somebody weighing 200 pounds might be able to stand on two bean cans without crushing them, but if the experiment failed it would make quite a mess.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
6
Views
3K
  • · Replies 69 ·
3
Replies
69
Views
5K
Replies
6
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 2 ·
Replies
2
Views
7K
  • · Replies 9 ·
Replies
9
Views
8K
  • · Replies 10 ·
Replies
10
Views
3K