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Forces on a pressurized tin can of beans

  1. Nov 15, 2013 #1
    Hi

    So I'm trying to find out how much force a tin can, can support before failing. The can will be stood up as it should be with a force applied over the top across the area of the can.

    I've tried the process of short column buckling to no avail.

    I've also tried axial and hoop stress for thin walled pressurized vessels.

    I keep getting silly numbers and am now completely lost.

    Also, would you assume that pressure inside the can is the same as atmospheric?

    So here are the numbers:

    Length = 109mm
    Diameter = 74mm
    Assumed yield stress of 590n/mm^2
    Atmospheric pressure = 0.101325n/mm^2

    Any direction or help would put my mind at ease, thanks

    I've found http://ntrs.nasa.gov/archive/nasa/casi.ntrs.nasa.gov/19690013955_1969013955.pdf
    Is page 14 the part im look for?

    Thanks again.
     
    Last edited: Nov 15, 2013
  2. jcsd
  3. Nov 15, 2013 #2

    SteamKing

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    Without knowing the thickness of metal in the can, you won't be able to even hazard a guess. It is also important to know if the sides of the can are rolled straight or if they might have any corrugations.
     
  4. Nov 15, 2013 #3
    Yea, sorry forgot to include that...

    Thickness = 0.4mm

    The sides are corrugated, but im just after the basic theory of the crushing force needed.

    I've got 53683.1N using Axial stress for thin walled cylinders

    Also tried a basic calculation of Stress = F/A + Pressure*pi*r^2 and rearrange for F

    I've also found that the internal pressure of a can of beans is 30psi or 206842.72 N/m^2

    Thanks alot
     
    Last edited: Nov 15, 2013
  5. Nov 17, 2013 #4
    No ideas? :<
     
  6. Nov 17, 2013 #5

    SteamKing

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    If your can of beans has an internal pressure of 30 psi, I suspect that the beans have spoiled. Usually, canned food is vacuum packed to eliminate any air inside the can which might promote spoilage of the contents. Carbonated beverages obviously are an exception, as the internal pressure inside the can provides resistance to collapse of the can.
     
  7. Nov 17, 2013 #6
    If the can is vacuum packed, wouldn't that mean the tin has negative internal pressure and would deform laterally?
     
  8. Nov 17, 2013 #7

    SteamKing

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    Not necessarily. Although cans are not infinitely strong, they do have some strength. That's why the thickness of the metal and what kind of corrugations are important in trying to determine the strength of the can. After all, even if a perfect vacuum forms inside the can, the maximum atmospheric pressure is still only about 15 psi.
     
  9. Nov 17, 2013 #8

    AlephZero

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    Be careful with that word "only". I prefer to think of it as nearly 1 ton per square foot, which doesn't sound quite so puny!

    With the OP's can dimensions, 15 psi is about 100 pounds force on each end of the can. Somebody weighing 200 pounds might be able to stand on two bean cans without crushing them, but if the experiment failed it would make quite a mess.
     
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