Forces on a Solid Disk: Determining F3

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SUMMARY

The discussion focuses on calculating the magnitude of force F3 acting on a solid disk with a mass of 3.6 kg and a radius of 2.9 meters. The forces F1 and F2 are applied with magnitudes of 47 Newtons in specified directions. Using the moment of inertia formula I = 1/2 M R², the calculated answer for F3 is 96.72 Newtons after the disk rotates 7 times counter-clockwise in 13 seconds.

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Homework Statement



Three forces of F1, F2, and F3 are applied to a solid disk with a mass of 3.6 kg and radius of 2.9 meters. F1 is directly above the center of the disk with a magnitude of 47 Newtons directed in the positive x direction, F2 is directly to the right of the center and has a magnitude of 47 Newtons directed in the negative y direction, and F3 is directly to the left of the center and is also directed in the negative y direction. If the disk is initially at rest and then rotates about its center 7 rotations counter-clockwise (positive direction) in a time of 13 seconds, what is the magnitude of F3 in Newtons?

Homework Equations



The moment of inertia for the disk about its center is I = 1/2 M R2.

The Attempt at a Solution



Answer comes to be 96.72. I have no idea how to get that answer
 
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Hi Paulie! :wink:

Show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:
 

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