A particle of mass m kilograms is acted on by two forces F and F with magnitudes 3*sqr-root 5 newtons and sqr-root 5 newtons and directions parallel to the vectors i+2j and i-2j respectively. The particle is initially at a position given by the vector 2i+j i was told to calculate the cartesian components of F and F and hence calculate the total force F + F, acting on the particle in component form MY SOLUTION i got F as: x=3*(root5)*cos(theta) y= 3*(root5)*sin(theta) i got F as: x=(root5)*cos(theta) y= (root5)*sin(theta) and then F + F as: F[x] = 4*(root5)*cos(theta) F[y] = 4*(root5)*sin(theta) i was just wondering if i have done it right ??? from there i need to show the couple of the total force about the point with position vector i is zero..................does any understand this part or know how to do it ??????