(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Find the general solution for:

y''-2y'+y=e^{x}/x

2. Relevant equations

NONE - not an initial value problem

3. The attempt at a solution

Solve the homogeneous first:

r^{2}-2r+1=0

r=1 as a double root

So:

y_{1}=c_{1}e^{x}

y_{2}=c_{2}xe^{x}

...but what in God's name is the form for the particular Y (based on the right side of the equation?). I suppose it's the "hard part" of this exercise but I've tried a couple and still don't see it.

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Form of particular solution for y''-2y'+y=(e^2)/x

**Physics Forums | Science Articles, Homework Help, Discussion**