(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Find the general solution for:

y''-2y'+y=e^{x}/x

2. Relevant equations

NONE - not an initial value problem

3. The attempt at a solution

Solve the homogeneous first:

r^{2}-2r+1=0

r=1 as a double root

So:

y_{1}=c_{1}e^{x}

y_{2}=c_{2}xe^{x}

...but what in God's name is the form for the particular Y (based on the right side of the equation?). I suppose it's the "hard part" of this exercise but I've tried a couple and still don't see it.

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# Homework Help: Form of particular solution for y''-2y'+y=(e^2)/x

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