Average Force Formula - Solving for Force

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SUMMARY

The average force required to stop a 6.0 g bullet traveling at 350 m/s in 1.8 ms is calculated using the impulse-momentum theorem. The formula for average force is derived from the change in momentum divided by the change in time, represented as F = Δp / Δt. In this case, the change in momentum (Δp) is 2100 kg·m/s, leading to an average force of approximately -1.2 x 10^3 N when rounded. This calculation confirms the teacher's provided answer.

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  • Understanding of impulse-momentum theorem
  • Basic knowledge of momentum and force equations
  • Familiarity with unit conversions (grams to kilograms)
  • Ability to perform calculations involving time in milliseconds
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wyclefchick
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[SOLVED] Formula for average force?

In a ballistics test at the police department, Officer Rios fires a 6.0 g bullet at 350 m/s into a container that stops it in 1.8 ms. What is the average force that stops the bullet?

can anyone help me to do this? or just give me the formula? The teacher gave us the right answer and it's -1.2 x 10^3N
 
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The average force is the change in momentum divided by the change in time.
 
This is just an impulse-momentum theorem problem. Impulse = Change in momentum. Impulse is F*delta t (t=time of impact) and change in momentum is just final momentum - initial momentum. Good luck
 
delta p= J
and J= F(delta t)

so

delta p=6.0g(350m/s)
delta p=2100
2100/1.8=1166.6666667

is that the same thing as 1.2x10^3?
 
wyclefchick said:
delta p= J
and J= F(delta t)

so

delta p=6.0g(350m/s)
delta p=2100
2100/1.8=1166.6666667

is that the same thing as 1.2x10^3?

It would be rounded to 1.2x10^3, yes.
 
thank you so much guys!
 
wyclefchick said:
thank you so much guys!

You're welcome (I'll speak on behalf of the people that actually helped you! :smile:)
 

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