Formula for electric potential energy

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Discussion Overview

The discussion revolves around the formula for electric potential energy in the context of a velocity selector apparatus, specifically examining the relationship between electric potential, charge, and kinetic energy. Participants explore the derivation and implications of the equation qV = 1/2 mv^2.

Discussion Character

  • Technical explanation, Conceptual clarification

Main Points Raised

  • One participant questions the origin of the left-hand side of the equation qV = 1/2 mv^2, seeking clarification on its derivation.
  • Another participant explains that the left-hand side represents the energy gained by a charge q moving through a potential difference V, describing it as the work done by the electric field on the charge.
  • A third participant suggests reviewing the concept of work done by an electric field for further understanding.
  • Another participant reiterates that the expression indicates the kinetic energy gained by a charge q while moving in an electric potential v.

Areas of Agreement / Disagreement

Participants generally agree on the interpretation of the equation in terms of energy gained by a charge in an electric field, but there is no consensus on the derivation of the left-hand side of the equation.

Contextual Notes

Some assumptions regarding the definitions of electric potential and kinetic energy may not be explicitly stated, and the discussion does not resolve the derivation question raised.

darksyesider
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In a velocity selector apparatus, i had an electric potential set across two points, and a proton at rest at one end. The potential was 350 V.

My instructor used :

qV = 1/2 mv^2 to find the velocity at the end of the apparatus.

Where did the left hand side of the eqn come from??
 
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darksyesider said:
qV = 1/2 mv^2 to find the velocity at the end of the apparatus.

Where did the left hand side of the eqn come from??
That describes the energy gained by a charge q moving through a potential difference V. (The work done by the field on the charge.)
 
qv=(0.5)mv^2
This expression indicates Kinetic Energy gained by a body with charge q while moving in a region of Electric potential v.
 

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