Formula for working out power produced by petrol being burnt in an engine

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SUMMARY

The discussion focuses on calculating the power produced by petrol combustion in an engine, specifically for a car traveling at 60 mph with a fuel consumption of 20 mpg. Key parameters include the density of petrol at 0.84 kg/l and the heat of combustion at 47,302 kJ/kg. The calculation involves converting energy from kJ to joules and then determining power in watts before converting to horsepower (hp) using the conversion factor of 745.7 watts per hp. The formula requires understanding the relationship between energy, time, and power.

PREREQUISITES
  • Understanding of basic physics concepts such as power and energy
  • Familiarity with unit conversions (e.g., gallons to liters, kJ to joules)
  • Knowledge of combustion properties of petrol
  • Basic mathematical skills for applying formulas
NEXT STEPS
  • Research the formula for calculating power from fuel consumption
  • Learn about the thermodynamics of combustion processes
  • Explore unit conversion techniques for energy and power
  • Investigate the efficiency of petrol engines and factors affecting performance
USEFUL FOR

Students in engineering or physics, automotive engineers, and anyone interested in understanding the energy output of petrol combustion in engines.

clifftifer
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Iam not looking for the answer, I would just like to pointed in the right direction with the formula which would help me work this out. Its been a number of years since I have had to do this. (AN EXTREMELY MATURE STUDENT) Thank you

If the fuel consumption of a car, traveling at a steady 60 mph, is 20 mpg what is the power produced by the petrol being burnt in the engine? [Assume that the density of petrol is 0.84 kg/l and the heat of combustion of petrol is 47 302 kJ/kg]
 
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Hi clifftifer! Welcome to PF :smile:

Power is the rate of energy used up or work done in unit time. Can you find this from the given information??
 
clifftifer said:
Iam not looking for the answer...
And proper PF members wouldn't give it to you, even if you asked politely.

Infinitum said:
Hi clifftifer! Welcome to PF :smile:

Power is the rate of energy used up or work done in unit time. Can you find this from the given information??

I had to throw in a few of other bits of information before I could come up with the answer:

1 watt = 1 joule/second
3.785 liters = 1 gallon
3600 seconds = 1 hour
745.7 watts = 1 hp​

to yield the answer in hp.

To start, my equation looked like:
x watts = 47,302,000 joules/kg * .......​

I ended up with joules/second, and then converted to hp.

Simple plug and chug, as we used to call it. hmmm... Do people still use that phrase; "plug and chug"?
 

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