Formula to find maximum kinetic energy?

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Homework Statement



Work Function=3.6 EV
Wavelength=250nm, UV
Maximum kinetic energy=?


Homework Equations



E=hf

Formulas from mark scheme:
E = hc/λ
hc/λ – Φ

The Attempt at a Solution



I had a vague idea of what to do, I just didn't understand why in the second formula from the mark scheme the work function is taken away from E
 
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I haven't worked with this for a while, but isn't it just the conservation of energy? You are using the energy of the incident 250 nm photon to pull the particle from the surface (the work function) and the rest of the photon's energy goes into kinetic energy:
KE=hc/λ – Φ.
 
It's so much simpler now that you've put it that way. Thank you so much! :'D