Formulating x^n Coordinate System for Non-Rectangular/Spherical Riemann Manifold

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SUMMARY

The discussion focuses on formulating the x^{n} coordinate system, specifically for non-rectangular or spherical Riemann manifolds. Participants emphasize the necessity of parameterizing a curve with respect to a parameter "s" to differentiate the coordinates effectively. The suggested approach involves defining a curve parameterized by "s" and expressing the coordinates as x^{n}(s) = (x^{1}(s), x^{2}(s), x^{3}(s), x^{4}(s)), allowing for the computation of the tangent vector via the derivative dx^{n}/ds. Additionally, participants recommend creating custom coordinates, such as u and v for 2D surfaces, to facilitate this process.

PREREQUISITES
  • Understanding of Riemannian geometry and manifolds
  • Familiarity with parameterization of curves
  • Knowledge of differentiation in multi-variable calculus
  • Basic concepts of tangent vectors and their applications
NEXT STEPS
  • Study the principles of Riemannian geometry and coordinate systems
  • Learn about parameterization techniques for curves in higher dimensions
  • Explore differentiation methods for functions on manifolds
  • Investigate the construction of custom coordinate systems for complex geometries
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Mathematicians, physicists, and students specializing in differential geometry, particularly those working with Riemannian manifolds and coordinate systems.

Philosophaie
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I want to be able to formulate [tex]x^{n}[/tex] coordinate system.
[tex]x^{n} =(x^{1}, x^{2}, x^{3}, x^{4})[/tex]
How do you do this when the Riemann Manifold is not rectangular or spherical?
Also how do you differentiate with respect to "s" in that case.
[tex]\frac{dx^n}{ds}[/tex]
 
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Philosophaie said:
I want to be able to formulate [tex]x^{n}[/tex] coordinate system.
[tex]x^{n} =(x^{1}, x^{2}, x^{3}, x^{4})[/tex]
How do you do this when the Riemann Manifold is not rectangular or spherical?
Also how do you differentiate with respect to "s" in that case.
[tex]\frac{dx^n}{ds}[/tex]

you can not simply do ##\frac{dx^n}{ds}##, because you do not have a parameter ##s##.

You should do something like this.
Make up a curve which is parameterized by ##s##.
##s## is your parameter along the curve.

Now you have

##x^{n}(s) = (x^{1}(s), x^{2}(s), x^{3}(s), x^{4}(s))##

And now you can do ##\frac{dx^n}{ds}## just fine.
Which is your tangent vector to the curve (might not be unit length).

Philosophaie said:
How do you do this when the Riemann Manifold is not rectangular or spherical?

Make your own coordinates.
For a 2d-surface you could use ##u## and ##v## as coordinates.

What do you want to do?
 

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