Found half an answer, I with the direction please.

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SUMMARY

The discussion centers on calculating the magnitude and direction of a projectile's initial velocity, specifically with horizontal and vertical components of 10 m/s and 20 m/s, respectively. The correct magnitude of the velocity is determined to be 22 m/s, while the angle of projection is confirmed to be 63 degrees. The user initially struggled with the trigonometric approach but ultimately resolved the issue by recognizing the right triangle formed by the velocity components and applying the tangent function.

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Homework Statement



A projectile is launched with a horizontal velocity of 10 m/s and a vertical velocity of 20 m/s. What is the magnitude and direction of the projectile’s initial velocity?

The Attempt at a Solution

I've tried using the trigonometric method but I end up with only 1 side and 1 angle which isn't good. I could logically think that since one side is 20 and one side is 10, the angle would be

90 / 3 = 30

30 * 2 = 60

But the answer sheet says 63 degrees. :"(
I found the magnitude but the problem is I can't find the direction. More specifically, at what degree is it traveling at.

The magnitude is 22.

So it should be

22 m/s [Up x Horizontal]

x = an unknown angle

I'm having trouble finding the value of x.

Than you. :3

NVM GOT IT. LOL :D
 
Last edited:
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nesan said:

Homework Statement



A projectile is launched with a horizontal velocity of 10 m/s and a vertical velocity of 20 m/s. What is the magnitude and direction of the projectile’s initial velocity?

The Attempt at a Solution




I've tried using the trigonometric method but I end up with only 1 side and 1 angle which isn't good. I could logically think that since one side is 20 and one side is 10, the angle would be

90 / 3 = 30

30 * 2 = 60

But the answer sheet says 63 degrees. :"(



I found the magnitude but the problem is I can't find the direction. More specifically, at what degree is it traveling at.

The magnitude is 22.

So it should be

22 m/s [Up x Horizontal]

x = an unknown angle

I'm having trouble finding the value of x.

Than you. :3

NVM GOT IT. LOL :D


Have you drawn a picture?
If you did you would see a right-angled triangle, and just use the Tangent function.
 

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