seifkhalil
- 1
- 0
It helps us to help you if you attempt the problems as well. I'll type them out so you can see how to do it and so as not to inflict a word file on more people than we have to...seifkhalil said:Hi, I need help in 4 questions. I need their answers if possible.
Thanks, SimonSimon Bridge said:It helps us to help you if you attempt the problems as well. I'll type them out so you can see how to do it and so as not to inflict a word file on more people than we have to...
seifkhalil, what do you know about this problem? I presume that you are taking a "Differential Equations" course. Do you recognise this as being a "linear equation with constant coefficients"? Do you understand that the first thing you need to do is find independent solutions to the "associated homogeneous equation" which is1. Solve the following DE:
$$ \frac{d^2y}{dx^2}+3\frac{dy}{dx}+2y=2x+e^{-x} $$
Okay, do you know what the "method of reduction or order" is? Since you are told that [itex]e^x[/itex] is as solution, look for another of the form [itex]y(x)= u(x)e^x[/itex]. Put that into the given equation and it will reduce to a first order equation for u(x).2. Given that ##y_1 = e^x## is a solution of the following homogeneous differential equation :
$$y^{\prime\prime}-3y^\prime+2y=0$$ ...use the method of reduction of order to find a second solution y2 . Hence, find the general solution of the nonhomogeneous differential equation :
$$y^{\prime\prime}-3y^\prime+2y=5e^{3x}$$
Do you know what the "Laplace transform" is? The Laplace transform of function f(x) is given by3. 3- i) Find the Laplace transform of the following functions:
a) ##f(t)= \big ( 1-e^{t/2} \big )^2##
b) ##f(t)=\big ( \sin t + \cos t \big )^2##
There is no simple way, such as integration, to find an inverse Laplace transform. You look up the basic ones in a table of transforms. You can typically use "partial fractions" to reduce fractions such as these to the "basic" ones.ii) Find the inverse Laplace transform of the following functions:
a) $$\frac{1}{s^2(s-2)}$$ b) $$\frac{9s+14}{(s-2)(s^2+4)}$$
Take the Laplace transform of both sides, which will include "L(y)", the Laplace transform of the uknown function. Algebraically solve the equation for L(y) then use a table of inverse transforms to find y.4. Use Lapalace transform to solve the following IVP:
$$y^{\prime\prime}-6y^\prime+9y=t\; ,\; y(0)=0\; ,\; y^\prime(0)=1$$