Four-Vectors: Definition Issues & Exam Prep

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SUMMARY

A four-vector is defined as a set of four numbers, X=(X0, X1, X2, X3), representing an event in Minkowski space, where X0 is the time component and X1, X2, X3 are spatial components. A four-vector maintains its identity under Lorentz transformations, which is a key distinction from three-dimensional vectors. To verify that a vector is a four-vector, one can demonstrate its invariance under Lorentz transformations or show that contracting it with another four-vector yields a Lorentz-invariant scalar.

PREREQUISITES
  • Understanding of Minkowski space
  • Familiarity with Lorentz transformations
  • Knowledge of four-vector notation and Einstein summation convention
  • Basic concepts of Lorentz invariance
NEXT STEPS
  • Study the properties of Lorentz transformations in detail
  • Learn about the Einstein summation convention and its applications
  • Explore the concept of Lorentz invariance and its significance in physics
  • Review examples of four-vectors in special relativity
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Students preparing for relativity exams, physicists studying special relativity, and anyone interested in the mathematical foundations of four-vectors.

Bigfoots mum
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Im having some four-vector definition issues. I have a relativity exam coming up and they quite often ask about 4-vectors.

1) Does this definition sound ok?
'A four-vector is 4 numbers, say X=(X0, X1, X2, X3), used to describe an event in minkowski space. The 'zeroth' is the time component, while the other 3 components are the spatial components of a 3-vector. A four-vector differs from a 3-dimensional vector in that it can undergo a lorentz transformation and remain a four-vector. '
2) How do i show that a vector is actually a four vector?
Do i just show that it remains a valid four vector under a lorentz transformation?

Any help is greatly appreciated
thanks
 
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Hi, the best way to define 4 vectors are by their transformation properties, which is essentially what you have said. In equation form it is

\widehat{x}^{\mu}=\Lambda^{\mu}_{\nu}x^{\nu}

Here Lambda is the mu, nu component of the lorentz matrix, and the einstein summation convention is used.
 
Bigfoots mum said:
2) How do i show that a vector is actually a four vector?
Do i just show that it remains a valid four vector under a lorentz transformation?
Yep, that works. I think it's also possible to show that it's a four-vector by demonstrating that if you contract it with another four-vector, the result is Lorentz-invariant (i.e. is a scalar). Sometimes that might be easier.
 

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