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If a function f'(u) has Fourier coefficients anμ and bnμ, by integration one can make new coefficients Anμ ,Bnμ which include constants of integration.
My question how can I verify that :
Anμcos nτ + Bnμ sin nτ= -i/2 ((Bnμ) -Anμi) einτ- (Bnμ-iAnμ) e-inτ
I assume this is the complex form of Fourier series, but anyway
thanks for any clarifications.
My question how can I verify that :
Anμcos nτ + Bnμ sin nτ= -i/2 ((Bnμ) -Anμi) einτ- (Bnμ-iAnμ) e-inτ
I assume this is the complex form of Fourier series, but anyway
thanks for any clarifications.