Fourier series: Parseval's identity HELP

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SUMMARY

The discussion centers on the application of Parseval's identity in the context of Fourier series. Participants explore the derivation of Fourier coefficients and the conditions under which one can interchange summation and integration. Key points include the necessity of uniform convergence for the interchange to be valid and the importance of the function's continuity and integrability. The conversation highlights the mathematical rigor required in handling Fourier series and the implications of Riemann integration in this context.

PREREQUISITES
  • Understanding of Fourier series and Fourier coefficients
  • Familiarity with Riemann integration
  • Knowledge of uniform convergence of series of functions
  • Basic concepts of functional analysis
NEXT STEPS
  • Study the conditions for uniform convergence of Fourier series
  • Learn about Parseval's identity and its applications in signal processing
  • Explore the implications of Riemann integration in Fourier analysis
  • Investigate the properties of square integrable functions
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Mathematics students, educators, and professionals in fields involving signal processing or harmonic analysis who seek to deepen their understanding of Fourier series and their convergence properties.

sarahisme
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Hey all,

I am unsure how to do this problem... i find problems where i have to derive things quite difficult! :P

http://img143.imageshack.us/img143/744/picture2ao8.png

this is the Full Fourier series i think and so the Fourier coeffiecients would be given by:

http://img144.imageshack.us/img144/8200/picture5yv4.png

ok so first i need to take the inner product, so i did this:

http://img99.imageshack.us/img99/7193/picture4ol9.png

but then i am stuck... anyone got an idea of how to proceed from here?

Cheers! :)

Sarah
 
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How about writing the inner product in this form instead...

\int_{-L}^{+L}|f(x)|^2dx = \int_{-L}^{+L} f(x) \left( \frac{A_0}{2} + \sum_{n\geq 1} A_n\cos (\frac{n\pi x}{L})+B_n\sin (\frac{n\pi x}{L}) \right)dx

does this inspire you more? (It should)
 
quasar987 said:
How about writing the inner product in this form instead...

\int_{-L}^{+L}|f(x)|^2dx = \int_{-L}^{+L} f(x) \left( \frac{A_0}{2} + \sum_{n\geq 1} A_n\cos (\frac{n\pi x}{L})+B_n\sin (\frac{n\pi x}{L}) \right)dx

does this inspire you more? (It should)

it does actually, hold on... i'll post my answer in a sec
 
http://img136.imageshack.us/img136/8739/picture6tt5.png

however i do have one question, are we allowed to substitute the integral inside the summation? (i am have never heard of any rules telling me whether this is or is not allowed...)
 
Last edited by a moderator:
Haven't you covered series of functions (or at least sequences of functions) in an earlier class?
 
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not for a couple of years i don't think...

thanks for the help by the way :)
 
Strange, since Fourier series are precisely series of functions. In occurrence, sine and cosine. They are usually covered in a second analysis class together with the theory of Riemann integration.
 
yeah, we did Riemann integration about a year and half ago i think, in a first analysis class I'm pretty sure.
 
So when is it OK to move the integral inside the summation?
 
  • #10
Thm: If the series of function \sum_{n=1}^{\infty} f_n(x) converges uniformly towards S(x) on [a,b] and if f_n is integrable on [a,b] \forall n\in \mathbb{N}, then the function S is integrable on [a,b] and

\sum_{n=1}^{\infty}\int_a^b f_n(x)dx=\int_a^b \sum_{n=1}^{\infty} f_n(x)dx
 
  • #11
sarahisme said:
http://img136.imageshack.us/img136/8739/picture6tt5.png

however i do have one question, are we allowed to substitute the integral inside the summation? (i am have never heard of any rules telling me whether this is or is not allowed...)

In this case it is surely ok to include the integral in the summation. Don't know the rule exactly but I remember my professor claiming that it's ok to do the above one.

I will try to find supporting evidence in due course!
 
Last edited by a moderator:
  • #12
In this case, how do we check if the Fourier series converges uniformly to the f(x)?
Actually we don't know if the function f is continuous and C^1 in [-L,L] so I think that we can't "move the integral inside the summation". If it was saying, for example, that the function f is periodic with L=pi and f is square integrable than we could do this.
 
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