Fourier tr. of dirac delta in minkowski space

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SUMMARY

The Fourier space representation of the Dirac delta function in Minkowski space is defined by the equation: \delta^{4}(x-x') = \frac{1}{(2\pi)^{4}} \int_{M_{4}} d^{4}k \ e^{ik^{\mu}(x-x')_{\mu}}. The integral is taken over the four-dimensional Minkowski space, denoted as M_{4}, with the metric conventionally set to diag(+,-,-,-). The term kx represents a dot product in the Minkowski sense, which is crucial for understanding the behavior of the Dirac delta function in this context.

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fliptomato
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Hey everyone, a quick question: what is the Fourier space representation of the dirac delta function in minkowski space? It should be some integral over e^{ikx} (with some normalization with 2*pi's). I'm curious if the "kx" is a dot product in the minkowski or euclidean sense, and how one reasons this.

Any thoughts? =)
Flip
 
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Well, of course

[tex]\delta^{4}\left(x-x'\right) =\frac{1}{\left(2\pi\right)^4}\int_{M_{4}} d^{4}k \ e^{ik^{\mu}\left(x-x'\right)_{\mu}[/tex]

where the metric on [itex]M_{4}[/itex] is (conventionally) diag(+,-,-,-).

Daniel.
 

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