Fourier Transform of a sinc like equation

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SUMMARY

The discussion focuses on the Fourier Transform of the sinc function defined as y(t) = sin(200πt)/(πt). The user seeks to understand how the transformation affects the rectangular pulse representation, specifically the height and frequency range of the pulse. The transformation can be simplified using the relationship y(t) = 200 sinc(200t), which clarifies the scaling factor involved. The user also inquires about using the Fourier theorem to determine the area of the pulse at y(0), questioning whether it represents the entire area or just the central portion.

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  • Understanding of Fourier Transform principles
  • Familiarity with sinc functions and their properties
  • Knowledge of the Fourier theorem and its applications
  • Basic calculus for evaluating integrals
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Students and professionals in signal processing, electrical engineering, and applied mathematics who are looking to deepen their understanding of Fourier Transforms and their applications to sinc functions.

InquiringM1nd
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I have been given this y(t)=\frac{sin(200πt)}{πt}

All I want is to find, is how the rectangular pulse will look like if I take the transformation of the above. That "200" kind of confusing me, because it isn't a simple sinc(t)=\frac{sin(πt)}{πt}

I need somehow to find the height of the pulse and frequency range.

If I had Y(f) after the Transformation, could I just use Fourier theorem below

y(0) = \int_{-\infty}^\infty Y(f)\,\mathrm df

to find the rectangle area? But also, I don't understand, at y(0) , it is supposed to be the whole area of the pulse or just the area at the center of the rectangle?
 
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I'm honestly not well versed in Fourier transforms, so I'm afraid I can't quite help you there. But isn't y(t) basically...

y(t) = \frac{sin(200\pi t)}{\pi t} = 200 \frac{sin(200 \pi t)}{200 \pi t} = 200 sinc(200t)

I don't suppose you could utilize that?
 
Char. Limit said:
I'm honestly not well versed in Fourier transforms, so I'm afraid I can't quite help you there. But isn't y(t) basically...

y(t) = \frac{sin(200\pi t)}{\pi t} = 200 \frac{sin(200 \pi t)}{200 \pi t} = 200 sinc(200t)

I don't suppose you could utilize that?

oh lol, I am tired a lot, I guess -.-

Thanks.
 

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