Fraction of a 100kg Cube's Volume Floating in Fluid | Uniform Density

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SUMMARY

The discussion centers on calculating the fraction of a 100kg solid plastic cube's volume that floats above the surface of a fluid with a specific gravity of 1.2. Using Archimedes' principle, the buoyant force acting on the cube is equal to the weight of the fluid displaced. The participants emphasize the importance of correctly calculating the specific gravity of the cube to determine the volume submerged and, consequently, the volume floating above the fluid's surface.

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A solid plastic cube with uniform density (side length = 0.5m) of mass 100kg is placed in a vat of fluid whose specific gravity is 1.2. What fraction of the cube's volume floats above the surface of the fluid?


I couldn't figure this one out. I tried using the ration of SG's.
 
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Per Archimedes principle, an object immersed in a fluid is buoyed up by a force equal to the weight of the fluid displaced by the object. You can do the problem by ratios of the SG's, which gives the fraction of the cube's volume floating below the surface. Did you calculate the SG of the cube correctly?
 

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