- #1
Azelketh
- 40
- 0
How to calculate the fraction of stimulated photons that escape from a laser cavity
with
alpha=0.1 cm^-1
length of cavity=1mm
refractive index of laser cavity=3.2
the photons are assumed to be escaping into air so approx refractive index is 1.
Im assuming that alpha is some sort of stimulation coefficient, as its units indicate a quantity per length, for each photon traveling a distance D number of stimulated photons emitted =Dalpha
(im forced to assume this as I am not given any information on what alpha is supposed to represent, just a quantity and units)
I know that only photons incident upon the laser cavity / air boundary at angles less than the critical angle will escape, but i have no idea how to calculate how many stimluated photons would be incident within that angle range.
Can anyone point me in the correct direction?
with
alpha=0.1 cm^-1
length of cavity=1mm
refractive index of laser cavity=3.2
the photons are assumed to be escaping into air so approx refractive index is 1.
Im assuming that alpha is some sort of stimulation coefficient, as its units indicate a quantity per length, for each photon traveling a distance D number of stimulated photons emitted =Dalpha
(im forced to assume this as I am not given any information on what alpha is supposed to represent, just a quantity and units)
I know that only photons incident upon the laser cavity / air boundary at angles less than the critical angle will escape, but i have no idea how to calculate how many stimluated photons would be incident within that angle range.
Can anyone point me in the correct direction?