# Fraction Simplification of Impedances and Resistances

1. Oct 12, 2009

### Jordash

My algebra is really rusty, anyway I'm trying to simplify a Transfer Function so I have

H(jw)=ZL/R+ZL so ZL is the impedance of an inductor and R is the impedance of the Resistor, my question is how would I go about simplifying that transfer function into it's simplest form?

Thanks,

Jordan

2. Oct 12, 2009

### Delphi51

Well you could do ZL/R+ZL = ZL(1/R + 1) if that is a help.
But there is something odd about ZL/R+ZL. The first term has no units while the second has units of ohms.

I don't know what a "transfer function" is so I'm not much help!

3. Oct 12, 2009

### Jordash

Let me throw another one out there to hopefully make it easier to understand (don't worry about the transfer function)

so 2.2e3/2.2e3+i2pi10e-3

How would that be simplified or in simpler terms

a/a+b

How would you simplify that

The problem above would be i*2pi*f*L/R+i*2pi*f*L

f is the frequency and 2pi*f would give us the reactance of the Inductor so i'm trying to figure out how to simplify everything.