Question about output voltages and impedances

Click For Summary

Homework Help Overview

The discussion revolves around two problems involving output voltages and impedances in electrical circuits. The first problem requires determining the output voltage when the load resistance equals the source resistance, based on given measurements. The second problem involves calculating an unknown impedance using a voltage divider configuration.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between load resistance and output voltage, with some suggesting that two equations are necessary to solve for the unknowns. Others question whether there are alternative methods to find the output voltage based on the relationships between resistances and voltages.

Discussion Status

There is an ongoing exploration of different approaches to the problems, with some participants affirming the correctness of methods used while others express uncertainty about the methods being different from classroom practices. Guidance has been offered regarding the need for two equations to solve the first problem.

Contextual Notes

Participants note that the results may not align with typical classroom examples, indicating a potential challenge in applying learned concepts to these problems.

Mohamed Abdul

Homework Statement


1. For the first measurement, a load resistance Rload = 119Ohms results in an output voltage V(OUT) = 11Volts. For the second measurement, Rload = 11Ohms results in an output voltage V(OUT) = 3.2Volts. From these two measurements, determine the output voltage V(OUT) when Rload = Rsource. You will have to first determine Rsourceand Vsource to answer this question. Express your answer in Volts. Note that the answers will not necessarily be consistent with any source we have seen but should not be unreasonable.

2. A voltage divider is used to determine the input impedance of an unknown circuit. The circuit of figure 1 in the Wikipedia entry on the voltage divider (https://en.wikipedia.org/wiki/Voltage_divider) is used as the model. Assume that Vin = 12Volts, Z1 = 410Ohms, and Vout = 58% of Vin. Determine the value of Z2 if you assume the input impedance is totally resistive.

Homework Equations


Vout = Vin(R2/(R1+R2))

The Attempt at a Solution


For the first problem, I knew that the greater Rload, the closer Vout would be to the actual source voltage. Thus I assumed that Vsource was 11Volts since 119 Ohms >> 11 Ohms. Plugging that in the equation where R1=R2, I got:

Vout = 11(R/2R) -> Vout = 11(1/2) -> Vout = 5.5 Volts.

For the second one, I used the voltage divider formula with the impedences and got:
.65Vin = Vin(Z2/(Z1+Z2)) -> .65Z1 + .65 Z2 = Z2 -> .65Z1 = .35Z2 -> .65(352)/.35 = Z2 = 653.714 Ohms.

Overall I feel like my work was correct but I'm unsure if I used the correct methods. These are a bit different than what we do in class so I'm not too sure.
 
Last edited by a moderator:
Physics news on Phys.org
itB4czv.png

This is what the circuit looks like for the first problem, by the way. As of now I have managed to figure out the second question but I am still struggling with this one.
 

Attachments

  • itB4czv.png
    itB4czv.png
    9.8 KB · Views: 511
You have 2 unknowns (Vsource and Rsource) so you will need to write 2 equations using the two data points (119R, 11V and 11R, 3.2V) and solve them.
 
CWatters said:
You have 2 unknowns (Vsource and Rsource) so you will need to write 2 equations using the two data points (119R, 11V and 11R, 3.2V) and solve them.
Is that the only way to figure out the solution. Isn't there another way to find the output voltage by looking at the relationships between the resistances and voltages?
 
CWatters said:
You have 2 unknowns (Vsource and Rsource) so you will need to write 2 equations using the two data points (119R, 11V and 11R, 3.2V) and solve them.
I checked my answer using your method, and it was correct. Thank you very much for helping me.
 
Yes your method might work because 119 Ohms >> 11 Ohms. That won't always be the case.
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 15 ·
Replies
15
Views
3K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K