- #1
Mohamed Abdul
Homework Statement
1. For the first measurement, a load resistance Rload = 119Ohms results in an output voltage V(OUT) = 11Volts. For the second measurement, Rload = 11Ohms results in an output voltage V(OUT) = 3.2Volts. From these two measurements, determine the output voltage V(OUT) when Rload = Rsource. You will have to first determine Rsourceand Vsource to answer this question. Express your answer in Volts. Note that the answers will not necessarily be consistent with any source we have seen but should not be unreasonable.
2. A voltage divider is used to determine the input impedance of an unknown circuit. The circuit of figure 1 in the Wikipedia entry on the voltage divider (https://en.wikipedia.org/wiki/Voltage_divider) is used as the model. Assume that Vin = 12Volts, Z1 = 410Ohms, and Vout = 58% of Vin. Determine the value of Z2 if you assume the input impedance is totally resistive.
Homework Equations
Vout = Vin(R2/(R1+R2))
The Attempt at a Solution
For the first problem, I knew that the greater Rload, the closer Vout would be to the actual source voltage. Thus I assumed that Vsource was 11Volts since 119 Ohms >> 11 Ohms. Plugging that in the equation where R1=R2, I got:
Vout = 11(R/2R) -> Vout = 11(1/2) -> Vout = 5.5 Volts.
For the second one, I used the voltage divider formula with the impedences and got:
.65Vin = Vin(Z2/(Z1+Z2)) -> .65Z1 + .65 Z2 = Z2 -> .65Z1 = .35Z2 -> .65(352)/.35 = Z2 = 653.714 Ohms.
Overall I feel like my work was correct but I'm unsure if I used the correct methods. These are a bit different than what we do in class so I'm not too sure.
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