Fractional linear transformation--conformal mapping

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Discussion Overview

The discussion focuses on finding necessary and sufficient conditions on the real numbers $a$, $b$, $c$, and $d$ for the fractional linear transformation $$ f(z) = \frac{az + b}{cz + d} $$ to map the upper half-plane to itself. The scope includes mathematical reasoning and exploration of complex analysis concepts.

Discussion Character

  • Exploratory
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • Participants seek guidance on starting the problem of determining conditions for the transformation to map the upper half-plane to itself.
  • One participant suggests multiplying the transformation by the complex conjugate of the denominator to analyze the conditions needed for the imaginary part of the numerator to be positive.
  • Another participant asserts that the condition $ad > bc$ is necessary for the mapping.
  • A later reply confirms agreement with the condition $ad > bc$.

Areas of Agreement / Disagreement

There is partial agreement on the condition $ad > bc$, but the discussion does not resolve whether this is the only condition or if additional conditions are necessary.

Contextual Notes

The discussion does not clarify whether there are other conditions that may also be necessary or if the derived condition is sufficient on its own.

Dustinsfl
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Find necessary and sufficient conditions on the real numbers $a$, $b$, $c$, and $d$ such that the fractional linear transformation
$$
f(z) = \frac{az + b}{cz + d}
$$
maps the upper half plane to itself.

I just need some guidance on starting this one since I am not sure on how to begin.
 
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dwsmith said:
Find necessary and sufficient conditions on the real numbers $a$, $b$, $c$, and $d$ such that the fractional linear transformation
$$
f(z) = \frac{az + b}{cz + d}
$$
maps the upper half plane to itself.

I just need some guidance on starting this one since I am not sure on how to begin.
Begin by multiplying top and bottom by the complex conjugate of the denominator: $$f(z) = \dfrac{az + b}{cz + d} = \dfrac{(az + b)(c\overline{z} + d)}{(cz + d)(c\overline{z} + d)}.$$

The denominator in that last fraction is real, so you need to find the imaginary part of the numerator and investigate what makes it positive whenever $z$ has positive imaginary part.
 
Opalg said:
Begin by multiplying top and bottom by the complex conjugate of the denominator: $$f(z) = \dfrac{az + b}{cz + d} = \dfrac{(az + b)(c\overline{z} + d)}{(cz + d)(c\overline{z} + d)}.$$

The denominator in that last fraction is real, so you need to find the imaginary part of the numerator and investigate what makes it positive whenever $z$ has positive imaginary part.

So $ad > bc$
 
dwsmith said:
So $ad > bc$
(Yes)
 

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