Free Body Diagram Homework: Forces to Consider

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SUMMARY

The discussion focuses on the forces to consider when drawing a free body diagram for an elevator that is accelerating upwards. The primary forces identified are the tension force (Ft) acting upwards and the gravitational force (Fg) acting downwards. The correct representation requires Ft to be greater than Fg when the elevator accelerates upwards, as indicated by the equation Ft + Fg = Fnet = ma, where 'a' is the acceleration. The conversation confirms that the diagram is accurate under the specified conditions of upward acceleration.

PREREQUISITES
  • Understanding of Newton's Second Law (F=ma)
  • Knowledge of free body diagrams
  • Familiarity with forces: tension (Ft) and gravitational force (Fg)
  • Concept of uniform velocity versus acceleration
NEXT STEPS
  • Study the principles of free body diagrams in physics
  • Learn about the effects of acceleration on forces in systems
  • Explore examples of free body diagrams for different scenarios
  • Investigate the relationship between tension and gravitational forces in various contexts
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and forces, as well as educators looking to enhance their teaching of free body diagrams and Newton's laws.

dranseth
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Homework Statement


When drawing a freebody diagram for just an elevator, not the people in it, what are all the forces that we have to consider? I just used Fg down and Ft up, but because it is accelerating up, I made Ft greater.
 
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Just because the elevator is moving up, doesn't mean it is always accelerating up. It may only accelerate when it first starts moving and right before it stops at your floor. Otherwise, it may be moving with uniform velocity upwards.
 
Well, in the question it stated that it was accelerating... So was I right to have only the two forces Ft and Fg with Ft bigger?
 
dranseth said:
Well, in the question it stated that it was accelerating... So was I right to have only the two forces Ft and Fg with Ft bigger?
In that case, your diagram is correct to have Ft greater in magnitude than Fg, since Ft + Fg = Fnet = ma and a must be non-zero, and I'm assuming the elevator is accelerating in the direction of Ft. ;)
 
Last edited:

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