Free Fall Acceleration Problem

  • Thread starter chounx93
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  • #1
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Homework Statement



As a runaway scientific balloon ascends at 19.6 m/s, one of its instrument packages breaks free of a harness and free-falls. The figure below gives the vertical velocity of the package versus time, from before it breaks free to when it reaches the ground.
2-p-053.gif


(a) What maximum height above the break-free point does it rise?
(b) How high is the break-free point above the ground?


Homework Equations





The Attempt at a Solution



i know part A is 19.6 m
i just can't seem to get the correct answer for part B

these are the variables that i have and i think i'll need
V0=0 m/s
t=6.0 s
a=-9.8 m/s/s
y-y0=?

i used this kinematic equation
y-y0=vt-1/2at^2
but the answer still isn't correct
 

Answers and Replies

  • #2
kuruman
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The package is at the break-free point at time t = 2 s and it is moving up. Can you figure out by looking at the graph at what later time it is at the same point, moving down?
 
  • #3
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it's at the same point at t=4 s
 
  • #4
kuruman
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At t = 4 s the velocity is instantaneously zero. This mean maximum height.
 

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