Calculating Final Velocity in Free Fall from Given Displacement and Acceleration

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SUMMARY

The discussion focuses on calculating the final velocity of riders in free fall from a height of 27 meters before they begin to decelerate. Using the equation vf² = vi² + 2(acceleration)(displacement), where vi = 0 m/s, acceleration = 9.8 m/s², and displacement = 27 m, the final velocity (vf) is determined to be 23 m/s. The confusion arises from the misconception that the final velocity at ground level should be 0 m/s, which is incorrect as it refers to the velocity just before deceleration begins.

PREREQUISITES
  • Understanding of kinematic equations
  • Knowledge of free fall physics
  • Familiarity with acceleration due to gravity (9.8 m/s²)
  • Basic algebra for solving equations
NEXT STEPS
  • Study kinematic equations in detail, focusing on their applications in free fall scenarios
  • Explore the effects of air resistance on falling objects
  • Learn about energy conservation principles in free fall
  • Investigate real-world applications of free fall calculations in amusement park ride design
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Physics students, educators, and anyone interested in understanding the dynamics of free fall and motion before deceleration in practical scenarios.

Balsam
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Homework Statement


The Drop Zone drops riders 27m from rest before slowingthem to a stop. How fast are they moving before they start slowing down?

vf=? vi=0, di=27m[up], df=om, displacement=27m[down], acceleration=9.8m/s^2[down] Air resistance is negligable

Homework Equations


vf^2=vi^2+2(acceleration)(displacement)

The Attempt at a Solution


I already figured this out and got the right answer(23 m/s), but in this question, the final velocity isn't 0m/s. That confuses me, because the final position is when they are on the ground- shouldn't the final velocity be 0m/s.
 
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Balsam said:

Homework Statement


The Drop Zone drops riders 27m from rest before slowingthem to a stop. How fast are they moving before they start slowing down?

vf=? vi=0, di=27m[up], df=om, displacement=27m[down], acceleration=9.8m/s^2[down] Air resistance is negligable

Homework Equations


vf^2=vi^2+2(acceleration)(displacement)

The Attempt at a Solution


I already figured this out and got the right answer(23 m/s), but in this question, the final velocity isn't 0m/s. That confuses me, because the final position is when they are on the ground- shouldn't the final velocity be 0m/s.
Key word: How fast are they moving before they start slowing down? If the riders have a velocity of 0 m/s on the ground, they have come to a complete stop.
You can't move from A to B at 0 m/s.
 
SteamKing said:
Key word: How fast are they moving before they start slowing down? If the riders have a velocity of 0 m/s on the ground, they have come to a complete stop.
You can't move from A to B at 0 m/s.
That makes sense. Thank you.
 

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