Free Fall and gravitational acceleration

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SUMMARY

The discussion centers on calculating the gravitational acceleration (g) for a ball dropped from a height of 1.5 meters, which hits the ground in 0.54 seconds. The equation used is y = 1/2gt², leading to an initial calculation of g = 10.27 m/s². However, with more precise calculations, the correct value of g is determined to be 10.29 m/s². This value is notably higher than the accepted standard of 9.8 m/s², highlighting the importance of precision in calculations.

PREREQUISITES
  • Understanding of kinematic equations, specifically y = 1/2gt²
  • Basic knowledge of gravitational acceleration
  • Ability to perform algebraic manipulations
  • Familiarity with units of measurement in physics (meters, seconds)
NEXT STEPS
  • Review the derivation of the kinematic equation y = 1/2gt²
  • Learn about the factors affecting gravitational acceleration
  • Explore precision in calculations and significant figures in physics
  • Study the differences between theoretical and experimental values of g
USEFUL FOR

Students studying physics, educators teaching kinematics, and anyone interested in understanding gravitational acceleration and its calculations.

tgilli
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Homework Statement



A ball is dropped from 1.5 y(m) and hits the ground in .54 t(s). What is the value of g (m/s^2)?

The accepted value of g = 9.8m/s^2


Homework Equations


y=1/2gt^2


The Attempt at a Solution



I'm getting this wrong, but this is my attempt.

1.5 = 1/2g x .54^2
1.5 = 1/2 x .292
1.5 = .146
.146 / 1.5 =

10.27 g (m/s^2)

10.27 g (m/s^2) is close, but not correct. The correct answer is 10.29 m/s^2

Clarification would be appreciated.
 
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tgilli said:

Homework Statement



A ball is dropped from 1.5 y(m) and hits the ground in .54 t(s). What is the value of g (m/s^2)?

The accepted value of g = 9.8m/s^2


Homework Equations


y=1/2gt^2


The Attempt at a Solution



I'm getting this wrong, but this is my attempt.

1.5 = 1/2g x .54^2
1.5 = 1/2 x .292
1.5 = .146
.146 / 1.5 =

10.27 g (m/s^2)

10.27 g (m/s^2) is close, but not correct. The correct answer is 10.29 m/s^2

Clarification would be appreciated.

Calculate the expression with more precision. I get 10.288
 
LowlyPion said:
Calculate the expression with more precision. I get 10.288


Got it and understand. Thanks.
 

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