1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Free Fall and gravitational acceleration

  1. Oct 23, 2008 #1
    1. The problem statement, all variables and given/known data

    A ball is dropped from 1.5 y(m) and hits the ground in .54 t(s). What is the value of g (m/s^2)?

    The accepted value of g = 9.8m/s^2


    2. Relevant equations
    y=1/2gt^2


    3. The attempt at a solution

    I'm getting this wrong, but this is my attempt.

    1.5 = 1/2g x .54^2
    1.5 = 1/2 x .292
    1.5 = .146
    .146 / 1.5 =

    10.27 g (m/s^2)

    10.27 g (m/s^2) is close, but not correct. The correct answer is 10.29 m/s^2

    Clarification would be appreciated.
     
  2. jcsd
  3. Oct 23, 2008 #2

    LowlyPion

    User Avatar
    Homework Helper

    Calculate the expression with more precision. I get 10.288
     
  4. Oct 23, 2008 #3

    Got it and understand. Thanks.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Free Fall and gravitational acceleration
Loading...