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Homework Help: Free Fall and gravitational acceleration

  1. Oct 23, 2008 #1
    1. The problem statement, all variables and given/known data

    A ball is dropped from 1.5 y(m) and hits the ground in .54 t(s). What is the value of g (m/s^2)?

    The accepted value of g = 9.8m/s^2

    2. Relevant equations

    3. The attempt at a solution

    I'm getting this wrong, but this is my attempt.

    1.5 = 1/2g x .54^2
    1.5 = 1/2 x .292
    1.5 = .146
    .146 / 1.5 =

    10.27 g (m/s^2)

    10.27 g (m/s^2) is close, but not correct. The correct answer is 10.29 m/s^2

    Clarification would be appreciated.
  2. jcsd
  3. Oct 23, 2008 #2


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    Homework Helper

    Calculate the expression with more precision. I get 10.288
  4. Oct 23, 2008 #3

    Got it and understand. Thanks.
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