Free Fall and max altitude Question

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SUMMARY

A ball thrown vertically upward from the ground with an initial speed of 15 m/s reaches its maximum altitude in 1.5 seconds. The maximum altitude achieved by the ball is 11.25 meters. At t=2 seconds, the velocity of the ball is -15 m/s, indicating it is descending, and the acceleration remains constant at -9.81 m/s² due to gravity throughout its flight.

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  • Understanding of kinematic equations for uniformly accelerated motion
  • Knowledge of gravitational acceleration (9.81 m/s²)
  • Familiarity with concepts of initial velocity and maximum height
  • Basic algebra for solving equations
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  • Learn how to calculate maximum height using the formula h = (v² - u²) / (2a)
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oconn1
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A ball is thrown vertically upward from the ground with an intial speed of 15m/s. How long does it take the ball to reach its maximum altitude? What is its maximum altitude? Determine the velocity and accelartion of the ball at t=2s.

If anyone can help me with the relatively simple problem much thanks will be given! :)

ANY HELP IS GREAT!
 
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oconn1 said:
A ball is thrown vertically upward from the ground with an intial speed of 15m/s. How long does it take the ball to reach its maximum altitude? What is its maximum altitude? Determine the velocity and accelartion of the ball at t=2s.

One part of the questions you can answer right away is: what is the acceleration of the ball? Is it the same when the ball is thrown as it is later on, or does it change?

You are asked about the maximum altitude of the ball and when it reaches that point. The ball is traveling straight up and (presumably) falls straight back down. What is its velocity at the peak? What could you use to figure out how long it takes for that to happen? After that, you should have something else you can use to tell you how far up it gets when that happens.
 

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